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vova2212 [387]
3 years ago
15

Write the pair of fractions as a pair of fractions with a common denominator |

Mathematics
1 answer:
trapecia [35]3 years ago
5 0

Answer:

3/10 and 2/5 = 3/10 and 4/10

1/3 and 3/4 = 4/12 and 9/12

Step-by-step explanation:

For 3/10 and 2/5

* Find the lcm (least common multiple) of the denominators which are 10 and  

 5. The multiples of 10 are: 10, 20, 30 etc and the multiples of 5 are: 5, 10 15,

 etc. So, the lcm is 10. It is the smallest multiple that the denomitaotrs share.

* Next multiply the numerators (3 and 2) by whatever number you use to

  multiply the denominator by to get 10. For 3/10, the denominator stayed the

  same, so to get 10, you need to multiply 10 by 1. Do the same for the

  numerator. 3 x 1 = 3. So, the first factor pair is 3/10.

* The second factor pair is 2/5, so we are still using the lcm of 10. So, what

  do you need to multiply 5 by to get 10? The answer is 2. Now just multiply

  the numerator (2) by 2 and you get 4. The second factor pair is now 4/10.

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1. The company has agreed on a 9- character password format, comprised of uppercase letters, lower case letters, and digits (0-9
pochemuha

Answer: a) 1977060966, b) 146581344.

Step-by-step explanation:

Since we have given that

There are 10 numbers,

There are 26 lower case letters,

There are 26 upper case letters,

Since the first 3 characters have to be digits and next 6 can be upper or lower.

So, a) repetitions are allowed:

10^3\times (26+26)^6\\\\=10^3\times 52^6\\\\=1977060966

b) repetitions are not allowed:

^{10}P_3\times ^{52}C_6\\\\=720\times 20358520\\\\=146581344

Hence, a) 1977060966, b) 146581344.

5 0
3 years ago
CAN SOMEONE PLEASE SOLVE THIS PLEASE!!!!!!!!!!!!!!!!!!!!!!!!! NEED HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Yakvenalex [24]

Answer:

Are you cheating?

Step-by-step explanation:

5 0
4 years ago
A semicircle is cut out of a rectangular paperboard 24in long and 18n wide, as shown below. What is the perimeter of the paperbo
svet-max [94.6K]

Answer:

Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in

Step-by-step explanation:

Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.

Length = 24 in

Width = 18 in

Radius of the semi circle = Half of the width of the paperboard = \frac{18}{2} = 9 in

1) Circumference of the semi circle = π*radius

= 3.14*9

= 28.26 in

2) Perimeter of the paperboard that remains after the semicircle is removed

= Top + Left + Bottom + Right Circumference of the semi circle

= 24 + 18 + 24 + 28.26

= 94.26 in


5 0
3 years ago
Please help i can not fail this!!
ivann1987 [24]
No solution 
i got u fam
4 0
3 years ago
Read 2 more answers
Find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length.
Degger [83]

find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length

To find the perimeter of a triangle we add all the sides of the triangle

The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches

Perimeter of a triangle =

15 inches + 15 inches +   21 inches = 51 inches

So 51 inches is the perimeter

3 0
3 years ago
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