Since the congruent operator is ≅ and since AD is congruent to BD, I'm going to assume that you want to prove that AD is congruent to BD.
1. DE is equal to CD by definition since D is the midpoint of CE.
2. AE is equal to BC since opposite sides of a rectangle are equal to each other.
3. Angle AEC is equal to Angle BCE since all angles in a rectangle are right angles and all right angles are equal to each other.
4. Triangles ADE and BDC are congruent to each other because we have SAS congruence for both triangles.
5. AD is congruent to BC since they're corresponding sides of congruent triangles.
Answer:
The Math Club must sell at least 50 pies to reach the goal
The graph in the attached figure
Step-by-step explanation:
Let
x-----> the number of sold pies
we know that
The inequality that represent the situation is
Solve for x
Divide by 4 both sides
The solution is the interval ------> [50,∞)
All positive whole numbers greater than or equal to 50
In a number line the solution is the shaded area at right of x=50 (close circle)
The Math Club must sell at least 50 pies to reach the goal
using a graphing tool
see the attached figure
Answer:
$133.33
Step-by-step explanation:
When dealing with such a problem we can use the Rule of Three. This rule is basically used in order to find the missing value when dealing with a ratio. Like so...
12% of final price <======> $16
100% of final price <=====> x
Now we multiply the two available diagonal values together and divide by the last value in order to get the value of the variable, which in this case would be the original price in dollars
(100 * 16) / 12 = x
1600 / 12 = x
133.33 = x
Finally, we can see that the original price of the item was $133.33
The product is negative 81 t squared + 16 ⇒ 2nd answer
Step-by-step explanation:
The product of two binomials (ax + b)(cx + d), where a, b, c, and d are constant
- Multiply (ax) by (cx) ⇒ 1st × 1st
- Multiply (ax) by (d) and (b) by (cx) ⇒ ext-reams and nears
- Add the two products ⇒ like terms
- Multiply (b) by (d) ⇒ 2nd × 2nd
Let us find the product of (9 t - 4) and (-9 t - 4)
Multiply the 1st two terms
∵ (9 t)(-9 t) = -81 t²
Multiply the ext-reams
∵ (9 t)(-4) = -36 t
Multiply the nears
∵ (-4)(-9 t) = 36 t
Add the like terms
∵ -36 t + 36 t = 0
Multiply the 2nd two terms
∵ (-4)(-4) = 16
Write the answer
∴ (9 t - 4)(-9 t - 4) = -81 t² + 0 + 16
∴ (9 t - 4)(-9 t - 4) = -81 t² + 16
The product is -81 t² + 16
Learn more:
You can learn more about the product of algebraic expressions in brainly.com/question/1617787
#LearnwithBrainly
V= s^3
a=486/6=81
s=sqrt(81)=9
v=9^3=729
the volume of the cube is 729cm^3
