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3 years ago

Given ABCE is a rectangle, D is the midpoint of CE Prove AD =~ BD

Mathematics

1 answer:

Bas_tet [7]3 years ago

5 0

Since the congruent operator is â‰… and since AD is congruent to BD, I'm going to assume that you want to prove that AD is congruent to BD.
1. DE is equal to CD by definition since D is the midpoint of CE.
2. AE is equal to BC since opposite sides of a rectangle are equal to each other.
3. Angle AEC is equal to Angle BCE since all angles in a rectangle are right angles and all right angles are equal to each other.
4. Triangles ADE and BDC are congruent to each other because we have SAS congruence for both triangles.
5. AD is congruent to BC since they're corresponding sides of congruent triangles.

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3 years ago

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Ilya [14]

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True or False? The graph of sine can be used to construct the graph of the secant function.

amid [387]

True

Note that:

$secant \theta = \frac{1}{cos\theta}$

The graph of sine and cosine functions are very similar. They only have a shift in the x -axis.

That is, sin x = cos (90 - x)

Since there is a great similarity between the sine and cosine graphs, and the secant graph is an inverse of the cosine graph, the graph of sine can be used to construct the graph of the secant function

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since sec x = 1 / cos x

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therefore, sec x = 1 / sin (90 - x)

The graphs of the sine and secant functions are attached to this solution

Learn more here: brainly.com/question/9554579

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