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Sonja [21]
3 years ago
15

Suppose James randomly draws a card from a standard deck of 52 cards. He then places it back into the deck and draws a second ca

rd. A standard deck of cards contains four suits: clubs, diamonds, hearts, and spades. There are 13 cards in each suit, which includes three face cards: jack, queen, and king. What is the probability that James draws a queen card as the first card and a diamond card as the second card? Express your answer as a percentage precise to two decimal places.
Mathematics
1 answer:
qwelly [4]3 years ago
7 0

Answer:

1.92%

Step-by-step explanation:

The probability for first case, picking a queen out of deck, will be:

\frac{4}{52}

as there will be 4 queens in a deck, one of each suit.

For the second pick, the probability of picking a diamond card, will be:

\frac{13}{52}

here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).

Thus the net probability for both cases will be:

P = \frac{4}{52}  * \frac{13}{52}\\ P = \frac{1}{52}\\ P = 0.01923\\P = 1.923\%\\\\P = 1.92\%

Thus total probability for the combined two cases will be 1.92%

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On a coordinate plane, an exponential function has a horizontal asymptote of y = 0. The function curves up into the first quadra
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The sum of a rational number and an even integer is rational. A) Always True B) Sometimes True C) Usually True D) Never True
SOVA2 [1]
I think that the sum will always be a rational number
let's prove that


<span>any rational number can be represented as a/b where a and b are integers and b≠0

</span>and an integer is the counting numbers plus their negatives and 0
so like -4,-3,-2,-1,0,1,2,3,4....

<span>so, 2 rational numbers can be represented as

</span>a/b and c/d (where a,b,c,d are all integers and b≠0 and d≠0)

their sum is
a/b+c/d=
ad/bd+bc/bd=
(ad+bc)/bd

1. the numerator and denominator will be integers
2. that the denominator does not equal 0

alright
1.
we started with that they are all integers
ab+bc=?
if we multiply any 2 integers, we get an integer
<span>like 3*4=12 or -3*4=-12 or -3*-4=12, etc.
</span>even 0*4=0, that's an integer
the sum of any 2 integers is an integer
like 4+3=7, 3+(-4)=-1, 3+0=3, etc.
so we have established that the numerator is an integer

now the denominator
that is just a product of 2 integers so it is an integer


<span>2. we originally defined that b≠0 and d≠0 so we're good

</span>therefore, the sum of any 2 rational numbers will always be a rational number <span>is the correct answer.</span>
6 0
3 years ago
Several years​ ago, 39​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
BaLLatris [955]
<h2>Answer with explanation:</h2>

Let p be the population proportion  of parents who had children in grades​ K-12 were satisfied with the quality of education the students receive.

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Since , Confidence interval does not contain 0.39.

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