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3 years ago

Find the missing sum of a triangle

Mathematics

1 answer:

melamori03 [73]3 years ago

3 0

Answer:

where you supposed to add a picture or..?

Step-by-step explanation:

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A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h

julsineya [31]

Answer:

a. $P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

b. $E(x) = 0.3$

c. $S(x)=0.5196$

d. $E=5,000$

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

$P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\$

For binomial distribution:

$E(x)=np\\S(x)=\sqrt{np(1-p)}$

Therefore, the company can expect to win 0.3 bids and it is calculated as:

$E(x) = np = 3*0.1 = 0.3$

Additionally, the standard deviation of the number of bids won is:

$S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196$

Finally, the probability to won 1, 2 or 3 bids is equal to:

$P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001$

So, the expected profit for the company is equal to:

$E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000$

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0

3 years ago

A school plays a series of 6 soccer matches. For each match there are 3 possibilities: a win, a draw or a loss. How

Sphinxa [80]

Answer:

There are 729 possible results are there for the series

Step-by-step explanation:

If we have n trials, each with m possible outcomes, the total number of possible outcomes is:

$T = m^{n}$

In this question:

6 games(trials), so $n = 6$ .

Each with three possible outcomes, so $m = 3$

Then:

$T = 3^{6} = 729$

There are 729 possible results are there for the series

7 0

3 years ago

Please Help Me With All Four

svetlana [45]

Answer:

answer below

Step-by-step explanation:

a is: 0.8

b is : 2

c is: 5

d is: 12.5

6 0

3 years ago

Read 2 more answers

You are a real estate agent with ABC Real Estate company. You help sell a home for $155,000. The total commission is 6.5%. Your

gtnhenbr [62]

Answer:

$3,929.25.

Step-by-step explanation:

First, calculate the total commission. That's found by multiplying the selling price ($155,000) by 0.065. The result: The total commission is $10,075.

Your company receives 60% of that. So we multiply $10,075 by 0.60, obtaining $6,045.

Your share of the commission is 65% of that, so we multiply $6,045 by 0.65:

0.65($6,045) = $3,929.25.

Your personal share of the commission is thus $3,929.25.

4 0

3 years ago

2x-7=117 what is the value of x

Tcecarenko [31]

$2x - 7 = 117$