Am i right or am i wrong

If a plane can climb at 2,400 feet per minute, how many minutes are needed to climb to 60,000 feet?

cestrela7 [59]

Hi there --

If a plane can climb 2,400 feet per minute, it will need 25 minutes to reach 60,000 feet. // By dividing 60,000 (the needed feet) by 2,400 (the amount of feet the plane can climb per/min) you get 25 (the amount of mins needed to climb 60,000 feet)

Hope this helps! Have a great day! :)

3 0

2 years ago

Pls help meh...... with the question.....pls it's urgent ...........

HACTEHA [7]

Answer:

1.6962 = 1.70 (2 dp)

0.4247 = 0.425 to 3 dp

0.007395 = 0.007 to 3 dp

0.007395 = 0.0074 to 4 dp

32549 = 32500 to 3 significant figures

32549 = 32550 to 4 significant figures

909520 = 910000 to 3 significant figures

909520 = 909500 to 4 significant figures

Step-by-step explanation:

1.6962 = 1.70 (2 dp)

0.4247 = 0.425 to 3 dp

0.007395 = 0.007 to 3 dp

0.007395 = 0.0074 to 4 dp

32549 = 32500 to 3 significant figures

32549 = 32550 to 4 significant figures

909520 = 910000 to 3 significant figures

909520 = 909500 to 4 significant figures

5 0

3 years ago

Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)

DiKsa [7]

Answer:

The standard equation of the sphere is $(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Let the first endpoint be represented as $(x_{1}, y_{1}, z_{1})$ and the second endpoint be $(x_{2}, y_{2}, z_{2})$ .

Hence,

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})$

Midpoint = $(\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})$

Midpoint = $(\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\$

Midpoint = $(5, 5, 4)$

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

$d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }$

$d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}$

$d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}$

$d = \sqrt{16 +196 + 0$

$d =\sqrt{212}$

$d = 2\sqrt{53}$

This is the diameter

To find the radius, r

From $Radius = \frac{Diameter}{2}$

$Radius = \frac{2\sqrt{53} }{2}$

∴ $Radius = \sqrt{53}$

r = $\sqrt{53}$

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is $(5, 5, 4)$

Radius of the sphere is $\sqrt{53}$

The equation of a sphere of radius r and center $(h,k,l)$ is given by

$(x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}$

Hence, the equation of the sphere of radius $\sqrt{53}$ and center $(5, 5, 4)$ is

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}$

$(x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53$

This is the standard equation of the sphere

6 0

3 years ago

What is the total cost of a $150.00 necklace if the sales tax is 6.5%

LiRa [457]

The best thing to do is to find what 1% is, and you can do this by dividing 150 by 100.
150/100= 1.5
As you're looking for 6.5%, you've got to multiply 1.5 by 6.5
1.5*6.5= 9.75
You've then got to add 9.75 and 150 together
150+9.75= $159.75
Therefore, after the sales tax, the cost of the necklace is $159.75
Hope this helps :)

4 0

3 years ago

Describe the location of the point having the following coordinates.

denis23 [38]

we know that

If the point has an nonzero abscissa (x coordinate) then it can be located in any of the four quadrants

If the point has an negative ordinate (y coordinate) then it can be located in Quadrant III or Quadrant IV

therefore

the answer is the option

Quadrant III or Quadrant IV

7 0

3 years ago