You calculate the markup or markdown in absolute terms (you find by how much the quantity changed), and then you calculate the percent change relative to the original value. So they're really just another form of "increase - decrease" exercises.
Example:
A computer software retailer used a markup rate of 40%. Find the selling price of a computer game that cost the retailer $25.
The markup is 40% of the $25 cost, so the markup is:
(0.40)(25) = 10
Then the selling price, being the cost plus markup, is:
25 + 10 = 35
The item sold for $35.
Answer:
R(x) = 8999.93x
Step-by-step explanation:
The original price is $9000 per unit. The unit is x, so if you buy x units, you pay 9000x.
The original price function is
R(x) = 9000x
The discount is 7 cents per unit bought, so if you buy x units, the discount is 9x in cents, or 0.09x in dollars. This discount is subtracted from the original price, so the discounted price is
R(x) = 9000x - 0.07x
R(x) = 8999.93x
Answer: R(x) = 8999.93x
The (2x+4) would be obtuse and 76 would be acute
3x+21-12=8x-28
collect the like terms
3x-8x=-28(21-12=9)
-5x=-28-9
-5x=-37
x=7.4
Answer:
(−5, −11), because the point satisfies both equations
Step-by-step explanation:
A solution to a system is always the ordered pair that satisfies both equations. So this explanation is the only one that would make sense.
