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notka56 [123]
3 years ago
8

(2x^3-3x^2-19x+30)/(x-3)

Mathematics
2 answers:
FrozenT [24]3 years ago
7 0
Dkdoodwoskfkvglelwldlgltwkqkdof the answer is -8
NeX [460]3 years ago
4 0

Answer:

2x^3 + 3x - 10

Step-by-step explanation:

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The caller times at a customer service center has an exponential distribution with an average of 22 seconds. Find the probabilit
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Answer:

The probability that a randomly selected call time will be less than 30 seconds is 0.7443.

Step-by-step explanation:

We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.

Let X = caller times at a customer service center

The probability distribution (pdf) of the exponential distribution is given by;

f(x) = \lambda e^{-\lambda x} ; x > 0

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So,  22=\frac{1}{\lambda}  ⇒ \lambda=\frac{1}{22}

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To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;

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Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)

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                         =  1 - 0.2557

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