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3 years ago

You buy 3.18 pounds of peaches, 1.45 pounds of apples, and 2.06 pounds of pears. What is your total bill?

Mathematics

2 answers:

Mrrafil [7]3 years ago

6 0

Answer:

6.69 is the total amount of pounds

viktelen [127]3 years ago

6 0

6.69 is the answer. Bcause you add the hundreths place to get 19 carry the 1 add them together you got .69 the add the onesplace to get 6 then your answer is 6.69

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There are many toys in a kindergarten. The ratio of the number of dolls to the number of balls to the number of cars is 7:8:5. I

Nina [5.8K]

Answer:

There are 28 dolls, 32 balls, 20 cars for 80 total toys

Step-by-step explanation:

dolls : balls: cars: total

7 8 5 (7+8+5)

7 8 5 20

We have a total of 80

80/20 = 4

We need to multiply each number by 4

dolls : balls: cars: total

7*4 8*4 5*4 20*4

28 32 20 80

There are 28 dolls, 32 balls, 20 cars for 80 total toys

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3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

Mrs parker bought three pizzas for her class 27/8 of the pizza was eaten how many whole pizzas where. left and how many pizzas w

OverLord2011 [107]

27/8 = 3 3/8
3 whole pizzas were left
5/8 is left over because 8/8 - 3/8 = 5/8

7 0

3 years ago

You buy 3.18 pounds of peaches​, 1.45 pounds of apples​, and 2.06 pounds of pears. What is your total​ bill?

You buy 3.18 pounds of peaches, 1.45 pounds of apples, and 2.06 pounds of pears. What is your total bill?