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4 years ago

What is the interquartile range of the following data set? 300, 785, 670, 187, 760, 724

Mathematics

2 answers:

mylen [45]4 years ago

8 0

Answer:

C) 460

Step-by-step explanation:

The first step is to sort the data in ascending order:

187; 300; 670; 724; 760; 724

Then find the median separates the first and second half of the data. In this case it is between 670 and 724.

There are three values below the median, and the middle one, 300, is the first quartile.

There are three values above the median, and the middle one, 760, is the third quartile.

The interquartile range is the difference between the first and the third quartile:

$760-300=460$

Zinaida [17]4 years ago

3 0

The answer should be c

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4 years ago

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IgorLugansk [536]

Answer:

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3 years ago

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inessss [21]

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3 years ago

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The volume of a spherical sculpture is 256 ft³. Rhianna wants to estimate the surface area of the sculpture. To do the estimate,

Brrunno [24]

Answer:

192 $ft^2$

Step-by-step explanation:

Given that

Volume of spherical sculpture = 256 ft³

$\pi$ is used as 3.

To find:

Surface area of sculpture = ?

Solution:

First of all, let us learn about the formula for Volume and Surface Area of Sphere:

1. $Volume =\frac{4}{3}\pi r^3$

2. $Surface\ Area = 4\pi r^2$

Given volume is 256 ft³.

$256 = \dfrac{4}{3}\pi r^3\\\Rightarrow 256 = \dfrac{4}{3}\times 3 r^3\\\Rightarrow 256 = 4 r^3\\\Rightarrow r^3=64\\\Rightarrow \bold{r = 4\ ft}$

Now, let us put r = 4 in the formula of Surface Area to find the value of Surface Area:

$Surface\ Area = 4\pi 4^2 = 4 \times 3 \times 16 = \bold{192\ ft^2}$

So, approximate surface area of sculpture is 192 $ft^2$ .

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3 years ago