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2 years ago

One number is 10 times as large as another, and their difference is 81. Find the numbers.

Mathematics

2 answers:

marysya [2.9K]2 years ago

6 0

Answer:

Step-by-step explanation:

10x - x = 81

9x = 81

x = 9

larger number = 10 x 9 = 90

mihalych1998 [28]2 years ago

4 0

For this case we have that "x" is the variable that represents the smallest number to find. Let and the variable that represents the largest number, then: $y = 10x\\y-x = 81$

Substituting the first equation in the second:

$10x-x = 81\\9x = 81\\x = \frac {81} {9}\\x = 9$

So, the biggest number is:

$y = 10 * 9 \\y = 90$

Answer:

10x

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