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oksian1 [2.3K]
3 years ago
9

One number is 10 times as large as another, and their difference is 81. Find the numbers.

Mathematics
2 answers:
marysya [2.9K]3 years ago
6 0

Answer:

90

Step-by-step explanation:

10x - x = 81

9x = 81

x = 9

larger number = 10 x 9 = 90

mihalych1998 [28]3 years ago
4 0

For this case we have that "x" is the variable that represents the smallest number to find. Let and the variable that represents the largest number, then:y = 10x\\y-x = 81

Substituting the first equation in the second:

10x-x = 81\\9x = 81\\x = \frac {81} {9}\\x = 9

So, the biggest number is:

y = 10 * 9 \\y = 90

Answer:

10x

90

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