y-3)^{2} =16" alt="(x-4)^{2} ^+(y-3)^{2} =16" align="absmiddle" class="latex-formula">
Find the center and radius
(explanation please, I need help)
1 answer:
an equation for a circle has formula
(x-m)² + (y-n)² = r²
where (m,n) is its center
and r is its radius
so, the equation has center (4,3) and radius 4
the equation is derived from the pythagorean theorem
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