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10 months ago

Outline the process for inscribing a regular hexagon in a circle. Perform the construction in GeoGebra

Mathematics

1 answer:

mr_godi [17]10 months ago

4 0

The following are the general steps to draw a hexagon inscribed in a circle:

First draw a circle with center A through B:

Then the intersection points will be vertex C and vertex D of the hexagon. Doing this for each vertex (from left to right) we will get the following:

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In order for figure EFGH to be a trapozoid, which of the following must be true?

kicyunya [14]

You must connect all the letters to create the shape of a trapezoid

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3 years ago

I need some help on this. Not sure how to solve.

andreyandreev [35.5K]

Answer:

x = 9

Step-by-step explanation:

This shape is a 30-60-90 triangle, which means that the angles of the triangle are each 30°, 60° and 90°. Given that the measures of the angles of the triangle are known, as well as one side, we can find the measures of all the other sides (example attached). A 30-60-90 triangle is special because of the relationship of its sides. The hypotenuse (directly across from the 90° angle) is equal to twice the length (2x) of the shorter leg, in this case labeled 'x' and directly across from the 30° angle. The longer leg, across from the 60° angle, is equal to multiplying the shorter leg (x) by √3 or x√3.

Since the measure of the hypotenuse is given at 18, we can set the expression of that side equal to 18 and solve for x:

2x = 18 or x = 9

5 0

2 years ago

YOU CAN EARN YOURSEL A BRAINLEST! (0.<)

Gelneren [198K]

Answer:

P(x) = 0.50x - 5

Step-by-step explanation:

x = number of glasses sold

She charges $0.50 per glass, so her revenue is

R(x) = 0.50x

which is the amount of money she brings in

Her cost function is

C(x) = 5

assuming she only spends that $5.00 on the supplies mentioned.

The profit P(x) is the difference of revenue and cost

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = 0.50x - 5

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2 years ago

The class scores of a history test have a normal distribution with a mean Mu = 79 and a standard deviation Sigma = 7. If Opal’s

e-lub [12.9K]

Using the normal distribution, we got that expression for the z-score of her test score is

$z= \frac{72-29}{7} \\\\z=-7/7\\\\z=-1$

<h3>What is Normal Probability Distribution?</h3>

it's a type of probability distribution which is symmetric about the mean, it gives data near the mean are more frequent than data far from the mean.

Given that mean = $\mu=79$

and standard deviation = $\sigma = 7$

X=73

we know that formula of z-score is

$z=\frac{X-\mu}{\sigma}$

Hence Z-score can be calculated as

$z= \frac{72-29}{7} \\\\z=-7/7\\\\z=-1$

Using the normal distribution, we got that expression for the z-score of her test score is

$z= \frac{72-29}{7} \\\\z=-7/7\\\\z=-1$

To learn more about the normal distribution visit : brainly.com/question/24663213

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2 years ago

Find x. Round your answer to the nearest tenth of a degree.<br> 12

Scorpion4ik [409]

Answer:

एकबाजु जइने एक आदमी गाण्डो एक नवो मोबेल ले आल्यूं इजिएइए एक नवो पायो एक हकलो जलेबी नहे हे लेवू हे रमेस आमहतया एक हकलो जलेबी लायो नहे नहे हे रमेस उजाड़ीपणो एक आदमी टृऋट श्रडश्रबग ह़ठषज्ठद क्

२+२(४८३₹८)-९८२

ठथखथखदगददडरडरडराऐआ नहे लायो हे नानु हंगळाम मनखाम हे लेवू एक आदमी हे रमेस आमहतया हे लेवू हे रमेस उजाड़ीपणो एक नवो पायो एक हकलो जामगाँ लाओ हे लेवू एक हकलो लोण हे नानु हंगळाम एक नवो पाहकट लायो काले नवो घोण लायो नहे हे लेवू हे रमेस उजाड़ीपणो करतो हे नानु पामणा ने सोका रान्दो

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3 years ago