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4 years ago

What is the value of x to the nearest tenth? Question #4

Mathematics

1 answer:

yawa3891 [41]4 years ago

8 0

Tangent (37) = x / 2.1
x = tangent (37) * 2.1
x = 0.75355 * 2.1
x = 1.582455

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Which list shows the triangles in order from greatest area to least area

aleksandr82 [10.1K]

Answer:

H - Triangle Z, Triangle X, Triangle Y

Step-by-step explanation:

Triangle X area = rad(66.5) cm^3 ≈ 8.155cm^3

Triangle Y area = 8.15cm^3

Triangle Z area = (17.5/2)cm^3 = 8.75cm^3

8.75cm^3 > 8.155cm^3 > 8.15cm^3

Therefore:

Triangle Z area > Triangle X area > Triangle Y area

7 0

3 years ago

Ok so i need help,what is 5% of 225

aivan3 [116]

If you would like to know what is 5% of 225, you can calculate this using the following steps:

x = 5% of 225
x = 5/100 * 225
x = 11.25

Result: 5% of 225 is 11.25.

3 0

4 years ago

Read 2 more answers

If the sixth term in a geometric sequence is 1/625, and the common ratio is 15, find the explicit formula of the sequence.

Nonamiya [84]

Answer:

The explicit formula of the sequence is $a_n=5(\frac{1}{5})^{n-1}$ for $n \geq 2$

Step-by-step explanation:

Sixth term in a geometric sequence = $\frac{1}{625}$

Common ratio = $\frac{1}{5}$

Formula of nth term = $a_n=ar^{n-1}$

Substitute the values

So, $\frac{1}{625}=a(\frac{1}{5})^{6-1}\\\frac{1}{625}=a(\frac{1}{5})^{5}\\\frac{1}{625} \times 5^5=a$

5=a

Substitute the value in 1

So, $a_n=5(\frac{1}{5})^{n-1}$

So, Option C is true

Hence the explicit formula of the sequence is $a_n=5(\frac{1}{5})^{n-1}$ for $n \geq 2$

7 0

4 years ago

K=1/2 mv^2. Determine m when v=30 and k=4500

tamaranim1 [39]

$K=\frac{1}{2}mv^2$

when v=30 and k=4500
$4500=\frac{1}{2}m(30)^2$
$4500=\frac{1}{2}m900$
$4500=450m$
divide bot sides by 450
$10=m$

m=10

6 0

3 years ago

Read 2 more answers

Construct the indicated confidence interval for the population mean using the t-distribution. Assume the population is normally

DanielleElmas [232]

Using the t-distribution, it is found that the confidence interval is (14.2, 14.8).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm t\frac{s}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 18 - 1 = 17 df, is t = 2.1098.

The other parameters are given by:

$\overline{x} = 14.5, s = 0.68, n = 18$ .

Hence, the bounds of the interval are given by:

$\overline{x} - t\frac{s}{\sqrt{n}} = 14.5 - 2.1098\frac{0.68}{\sqrt{18}} = 14.2$

$\overline{x} + t\frac{s}{\sqrt{n}} = 14.5 + 2.1098\frac{0.68}{\sqrt{18}} = 14.8$

The confidence interval is (14.2, 14.8).

More can be learned about the t-distribution at brainly.com/question/16162795

4 0

3 years ago