All categories

3 years ago

Help help help on this

Mathematics

1 answer:

pantera1 [17]3 years ago

7 0

ANSWER

C. 2.402

EXPLANATION

Given that:

$log_{3}(2) = 0.631$

$log_{3}(7) = 1.771$

We want to evaluate:

$log_{3}(14) = log_{3}(2 \times 7)$

Use the product rule of logarithms.

$log_{a}(mn) = log_{a}(m) + log_{a}(n)$

$log_{3}(14) = log_{3}(2) + log_{3}(7)$

$log_{3}(14) = 0.631 + 1.771$

$log_{3}(14) = 2.402$

The third choice is correct.

You might be interested in

Please help me!!!!! How do you get 67.3 and 112.7 from .9228

antoniya [11.8K]

Answer and Step-by-step explanation:

You are correct in that we need to use the Law of Sines: $\frac{c}{sinC} =\frac{b}{sinB}=\frac{a}{sinA}$ .

Here, when we use the Law of Sines, we have: $\frac{28}{sin(63)}=\frac{29}{sinB}$ .

Cross multiply:

(sinB) * 28 = (sin63) * 29

28sinB ≈ 25.839

sinB ≈ 0.9228

Now, in order to solve for B, we need to use inverse sin ( $sin^{-1}$ ):

$sin^{-1}(sinB)=sin^{-1}(0.9228)$

The sines on the left cancel out, and we're left with:

B ≈ 67.3 degrees

Now, one thing to keep in mind when doing Law of Sines is that there is potentially more than one answer possible for the degree measure. The other degree measure can be found by subtracting this one from 180:

180 - 67.3 = 112.7 degrees.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number

Triss [41]

Answer:

By definition, the derivative of f(x) is

$lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

Let's use the definition for $f(x)=\frac{1}{x}$

$lim_{h\rightarrow 0} \frac{\frac{1}{x+h}-\frac{1}{x}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{x-(x+h)}{x(x+h)}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{(-1)h}{x^2+xh}}{h}=\\lim_{h\rightarrow 0} \frac{(-1)h}{h(x^2+xh)}=\\lim_{h\rightarrow 0} \frac{-1}{x^2+xh)}=\frac{-1}{x^2+x*0}=\frac{-1}{x^2}$