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Whitepunk [10]
3 years ago
11

Write y =1/8 x + 7 In standard form using integers

Mathematics
1 answer:
bagirrra123 [75]3 years ago
6 0
The equation is  y = 1/8x + 7

Standard form equation is Ax + By = C,  where A > = 0.

First eliminate the fractions by multiplying the equation by 8

8y = x + 56

Subtract x from each side

-x + 8y = 56

SInce x coeficient can't be negative multiply the equation by negative one.

<span>x - 8y = -56</span>

You might be interested in
5^n=0.2 need to find value of n
lozanna [386]

Answer:

Below

Step-by-step explanation:

5^n = 0.2

First write the number in exponential form with the base of 5 :

     5^n = 5^-1

Because the bases are the same, we can set the exponents as equal :

     x = -1

Hope this helps! Best of luck <3

6 0
2 years ago
3. At a bargain store, Jamal bought 2 items that each cost the same amount. Isaiah bought 3 items that each cost the same amount
coldgirl [10]

Answer:

  • $6.75 and $4.50

Step-by-step explanation:

a) <u>Jamal spent:</u>

  • 2x

<u>Isaiah spent:</u>

  • 3 (x - 2.25)

<u>The equation is:</u>

  • 2x = 3(x - 2.25)

b) <u>Solving the equation</u>

  • 2x = 3x - 6.75
  • 3x - 2x = 6.75
  • x = 6.75

c) <u>Jamal's items cost </u>

  • $6.75 each

<u>Isaiah's items cost </u>

  • $6.75 - $2.25 = $4.50 each
7 0
3 years ago
Suppose you estimated square root of 12 by averaging a square like rectngle.What would be a reasonable estimation?​
sesenic [268]

Answer:

3.5.

Step-by-step explanation:

3^2 = 9

and 4^2 = 16 so the square root is between 3 and 4.

Take a rectangle 3.4 by 3.6:

the area = 3.4 * 3.6 = 12.24 so an estimate of the square root could be 3.5.

3.5 * 3.5 = 12.25.

5 0
2 years ago
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
Does this table represent a function ? Why or why not
sammy [17]
No, because one x-value corresponds to two different y-values
4 0
3 years ago
Read 2 more answers
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