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Semmy [17]
3 years ago
8

Solve the following system of equations.

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0
The answer is B. 

The attached file is how I got the answer. 

Hope this helped :)

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-10x^2 +9+8x^2-5x+7=-2x^2-5x+16

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List the constant(s) in the following expression:<br><br><br><br> 4c - r + 3
sukhopar [10]
The constant is 3.

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3 years ago
A newspaper and three hot chocolates cost $7. Two newspapers and two hot chocolates cost $6. How much does one hot chocolate cos
pochemuha

Answer:

the cost of one hot chocolate is $2.

Step-by-step explanation:

Let x be the hot chocolate cost and y be the newspaper cost.

Given:

A newspaper and three hot chocolates cost $7

So, the equation is

3x+y=7--------(1)

Two newspapers and two hot chocolates cost $6

So, the second equation is.

2x+2y=6---------(2)

Find one hot chocolate cost?

Solve equation 1 for y.

3x+y=7

y=7-3x

Put y value in equation 2

2x+2(7-3x)=6

2x+14-6x=6

14-4x=6

-4x=6-14

-4x=-8

negative sign is cancelled both side.

x=\frac{8}{4}

x=2

Therefore, the cost of one hot chocolate is $2.

3 0
3 years ago
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165

5x5= 25
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25+144= 165
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