The given equation is confusing since it written straight
without any symbols or parenthesis. I can write the equation in two forms:
(1 / 4) d + 7 --->
1
and
(1 / 4 d) + 7 --->
2
For equation 1, the variable d is first multiplied by 1 /
4 before adding up with the number 7. So in this case, the correct phrase would
be something like:
“The sum of one fourth a number and seven”
For equation 2, this is more complicated since the
variable is on the denominator side. The number 1 is divided by the product of
4 and variable d then summed up with the number 7. The correct phrase for this
one would be something like:
“The sum of the quotient of one over four times a number
and seven”
Select which equation is the correct one.
The answer is 19,448 different
groups, using the formula from permutation and combinations C (n, r) = (n!) /
(r! (n-r)!) which calculates the number of times where r objects can be chosen
from n object.
So,
C (17,7) = (17!) / (7! *(17-7)!)
C (17,7) = (17!) / (7! *10!)
C (17,7) =
(17*16*15*14*13*12*11*10!) / (7! *10!) then eliminate 10!
C (17,7) = (17*16*15*14*13*12*11)
/ (7*6*5*4*3*2*1) = (98017920)(5040)
C (17,7) = 19,448 different
groups
Answer:
Step-by-step explanation:
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using the normal standard table or exce:
answer