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Alenkasestr [34]
3 years ago
9

Write the quadratic formula y=x^2-6x+7 in vertex form.

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

Step-by-step explanation:

Start like this: x^2 - 6x = -7. Now you have the x terms on one side and the constant on the other. Take half the linear term (-6x) which is 3 and then square that (9) and add it to both sides, giving you x^2 - 6x + 9 = -7+ 9, or x^2 - 6x + 9 = 2. Now make the left side into the perfect square binomial you created by completing the square: (x-3)^2 = 2, and then move the 2 over to get: (x-3)^2 - 2. That's the vertex form for a parabola with a vertex at (3, -2)

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Which statement about the equation is true
8090 [49]
They equal the same so I’m pretty sure it has no solution x
6 0
3 years ago
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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
sashaice [31]

Answer:

k = –10

Step-by-step explanation:

From the question given above, the following data were obtained:

f(x) = x³ – 6x² – 11x + k

Factor => x + 2

Value of K =?

Next, we shall obtained the value of x from x + 2. This is illustrated below:

x + 2 = 0

Collect like terms

x = 0 – 2

x = –2

Finally, we shall determine the value of k as illustrated below:

f(x) = x³ – 6x² – 11x + k

x = –2

Thus,

f(–2) = 0

x³ – 6x² – 11x + k = 0

(–2)³ – (–2)² – 11(–2) + k = 0

–8 – (4) + 22 + K = 0

–8 – 4 + 22 + K = 0

10 + k = 0

Collect like terms

k = 0 – 10

k = –10

Thus, the value of k is –10

7 0
3 years ago
(2x -2)^-3<br>can anyone help me with this?​
zzz [600]

Answer: See below

Step-by-step explanation:

When you see that something is to the power of a negative number, it is another way of saying 1 over.

(2x-2)^-^3=\frac{1}{(2x-2)^3} =\frac{1}{(2x-2)(4x^2-8x+4)} =\frac{1}{8x^3-8x^2+8x-8}

4 0
3 years ago
Factor completely 2w^5-10w^3
Kryger [21]
2w^5-10w^3=2w^3(w^2-5)
8 0
4 years ago
Write the quadratic function f(x) = x2 - 5x + 3 in vertex form. Complete the square to determine the maximum or minimum value of
enyata [817]

Answer:

a). Vertex form f the function f(x) = (x - 2.5)²+3.25

b). Maximum value of the function is (-3)

Step-by-step explanation:

a). f(x) = x² - 5x + 3

we have to write this function in the vertex form.

f(x) = x² - 2(2.5)x + 3

    = [(1)²x²- 2(2.5)x + (2.5)²-(2.5)²] + 3

    = (x - 2.5)²- 6.25 + 3

    = (x - 2.5)² - 3.25

So the vertex for of the function is

f(x) = (x - 2.5)² - 3.25

b). Given quadratic function f(x) = -x² - 6x + 6 is in the standard form of f(x) = ax² + bx + c.

By comparing the coefficients of both the functions,

a = -1, b = 6 and c = 6

Here the value of a is negative, therefore, the given parabola is opening downwards.

And the maximum will occur at

x=-\frac{b}{2a}

When we plug in the values,

x=-\frac{6}{2(-1)}

x = 3

Now to get the value of maximum of the function we will get the value of f(3).

f(3) = -(3)²- 6(3) + 6

f(3) = 9 - 18 + 6

f(3) = -3

Therefore, maximum value of the quadratic function is (-3).

4 0
3 years ago
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