Answer:
they are 10km 32 degrees far from each other
Step-by-step explanation:
scott - 100km - 30 degrees
spork - 110km - 62 degrees
how far = difference between them
as spork's distance and degrees are greater than scott we substract Scott's from spork's
110 - 100 = 10 km
62 - 30 = 32 degrees
they are 10km 32 degrees far from each other
Answer:
Step-by-step explanation:
2) 8=n+3/-2
we cross multiply
n+3=8*(-2)
n+3= -16
n= -16 - 3
n= -19
lets check if we are correct
8=-19+3/-2
8= -16/-2
-16/-2=8
4) 9=x/2+6
we first calculate the fraction
x/2+6
L. c. m is 2
x/2+6/1=4x + 8/2=12x/2
2 times 2=4 plus x = 4x
2 times 1 =2 plus 6= 8
thats how i got 4x + 8/2
back to the question
9=12x/2
cross multiply
12x=9*2
12x=18
x=18/12
we will use 2 to divide it
9/2
3 will divide
3/2
x=3/2
Answer:
Step-by-step explanation:
We can do this by cross multiplying.
14/6=x/21
=49/21
Answer:
The height of the trapezoid is 6.63 units
The perimeter of the trapezoid is 38 units
Step-by-step explanation:
Whenever a geometry problem is given, it is often useful if it is sketched out. A sketch of this problem can be found in the image attached.
A)
We can see that a right-angled triangle is formed between points BED, with line BE being the height, h.
To get the dimensions of the line EB, we subtract the dimensions of DC from AB. This will give 15 -5 = 10
hence the dimensions of the righ angled triangle are
DE= h
DB = 12 (diagonal)
EB = 10
From Pythagoras' theorem,

The height of the trapezoid is 6.63
B)
We can get the perimeter of the trapezoid by adding the dimensions of all four sides together.
This will be
AD + DC + CB + AB
However we can assume for this case that it is a symmetrical trapezoid, and hence AD = CB
Thus, perimeter =
2 (AD) + DC +AB
2(9) +5 +15 = 38.
The perimeter of the trapezoid is 38 units
6pi is the answer i believe