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Alenkasestr [34]
3 years ago
9

Write the quadratic formula y=x^2-6x+7 in vertex form.

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0

Answer:

Step-by-step explanation:

Start like this: x^2 - 6x = -7. Now you have the x terms on one side and the constant on the other. Take half the linear term (-6x) which is 3 and then square that (9) and add it to both sides, giving you x^2 - 6x + 9 = -7+ 9, or x^2 - 6x + 9 = 2. Now make the left side into the perfect square binomial you created by completing the square: (x-3)^2 = 2, and then move the 2 over to get: (x-3)^2 - 2. That's the vertex form for a parabola with a vertex at (3, -2)

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Which of the following angles is not coterminal with the other three?
jekas [21]

9514 1404 393

Answer:

  b.  17°

Step-by-step explanation:

All of the angles are 2nd-quadrant angles except 17°, which is a 1st-quadrant angle.

  17° is the odd angle

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When you compute ...

  mod(angle, 360), you get 163, 17, 163, 163.

4 0
3 years ago
Sketch the region that is common to the graphs of x ≥ 2,
Oliga [24]

a. Find the graph of their common region in the attachment

b. The area of the common region of the graphs is 8 units²

<h3>a. How to sketch the region common to the graphs?</h3>

Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

  • The graph of x ≥ 2 is the region right of the line x = 2.
  • The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
  • To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.

So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

  • height = 4 units and
  • base = 4 units

So, its area = 1/2 × height × base

= 1/2 × 4 units × 4 units

= 1/2 × 16 units²

= 8 units²

So, the area of the common region of the graphs is 8 units²

Learn more about region common to graphs here:

brainly.com/question/27932405

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6 0
1 year ago
Find the length of the missing side.
White raven [17]

Answer:

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So, this will be: 8^{2} + 12^{2} = c^{2}

By simplifying we get:

c = \sqrt{208}

The missing side is: 14.4 (rounded to the tenth)

3 0
2 years ago
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4vir4ik [10]

Answer:

$13.00

Step-by-step explanation:

8 0
3 years ago
Greg is designing a clock face. Using the center of the clock face as the origin, he keeps its diameter at 10 units. Match the p
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The center of the clock is taken as the origin.The clock is a circle with a diameter 10 units.Radius is half the diameter .Radius = 10 ÷2= 5 units.

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When it is  12 o'clock the hour hand is on positive of y axis.Coordinates of the point at 12 o'clock=(0,5)

When it is 3 o 'clock the hour hand is on positive of x axis .Coordinate of the point at 3o'clock is (5,0)

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At 9o'clock the hour hand is on negative of x axis .The coordinate of the point at 6o'clock is(-5,0)

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3 years ago
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