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vredina [299]
4 years ago
6

3/4 + 2/7 ft I need help

Mathematics
2 answers:
lisabon 2012 [21]4 years ago
5 0

Answer:

29/28ft or 1.03571428571ft

Step-by-step explanation:

that's just it

Viktor [21]4 years ago
5 0
29/28 or 1 and 1/28.



Explanation: 3/4 turns into 21/28 and then 2/7 turns into 8/28. Then 21+8=29 which would be 29/28
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12. Gezane Patez is paid $6.25 for each toy she assembles. Last week she assembled the following number of
Mars2501 [29]

Answer:

$668.75

Step-by-step explanation:

Find the total number of toys:

27 + 20 + 19 + 19 + 22 = 107 total toys

Then calculate the total money earned at a rate of $6.25 per toy:

107 × 6.25 = $668.75

5 0
4 years ago
I need help finding AC
poizon [28]
(a) is the right answer
C=4 and A=-8
so AC= 4 - (-8) = 4 + 8
AC=12

8 0
3 years ago
The recipe made eight servings but I only want to make a note for five people if the recipe for eight servings call for 2 cups o
Hunter-Best [27]
8 / 2 = 45 / x....8 servings to 2 cups = 45 servings to x cups
cross multiply
(8)(x) = (2)(45)
8x = 90
x = 90/8
x = 11 1/4 (or 11.25) cups of flour are needed <==
7 0
4 years ago
Please help!!!!!
CaHeK987 [17]

Answer: Answer from Plato

Step-by-step explanation:

8 0
3 years ago
A circle has diameter of 11cm
dlinn [17]

Since length of diagonal (  Diagonal= 9.9cm ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.

<u>Step-by-step explanation:</u>

Here we have , A circle has diameter of 11 cm  A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:

We know the concept that for any square to fit inside the circle without touching the edge of circle  , diagonal of square must be less than diameter of circle  . Let's find out length of diagonal by using Pythagoras Theorem :

Hypotenuse ^2 = Perpendicular^2+Base^2

For a square , Perpendicular = base = side

⇒ Diagonal^2 = 2(side)^2

⇒ Diagonal= \sqrt{2}(side)

⇒ Diagonal= \sqrt{2}(7)

⇒ Diagonal= 9.9cm

Since length of diagonal (  Diagonal= 9.9cm ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.

5 0
3 years ago
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