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Anvisha [2.4K]
2 years ago
13

Three boys and four girls enter a contest at the local movie theater. A randomly chosen winner will be awarded a free movie tick

et, a collectible poster,
or free popcorn. What is the probability that a girl will win free popcorn?
A 3/21 B 4/21 C 3/7 D 4/7
Mathematics
1 answer:
levacccp [35]2 years ago
6 0

Answer:

B. 4/21

Step-by-step explanation:

⇒This question is on probability

⇒Number of boys=3

⇒Number of girls=4

⇒P(S)= 4+3=7

Probability for a girl to win is= 4/7

We have 3 awards a free movie ticket, a collectible poster, or a free popcorn

P(S)= 3

Probability of being awarded a free popcorn = 1/3

The probability that a girl will win free popcorn =

4/7 * 1/3 = 4/21

hope i helped and have a wonderful day

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Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

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The information provided is:

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(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

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=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

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