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Luda [366]
3 years ago
5

Alan wants to find an image of a car he can use in a presentation. What button should he click in the Images group to run a sear

ch? A. Clip Art B. Online Images C. WordArt D. Internet Pictures
Computers and Technology
1 answer:
maksim [4K]3 years ago
3 0

Alan should click on the Clip Art section and then run a search by entering the keyword in the search menu.

A. Clip Art

<u>Explanation:</u>

Alan wants to find an image of a car that he can use in his presentation. It is always a good practice to include pictures and other media like videos, GIFs, and sound effects to make a presentation more engaging and interesting.

In order to include an image, Alan should click on the Clip Art section and then run a search by entering the keyword in the search menu. The clip art allows the user access to the saved images and to the internet for searching the required image.

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Write a function named print_backward that accepts a String as its parameter and prints the characters in the opposite order. Fo
noname [10]

Answer:

Here is the JavaScript code:

function print_backward(string) {

   var revString = "";

   for (var i = string.length - 1; i >= 0; i--) {

       revString += string[i];  }

   return revString; }

document.write(print_backward("hello there!"))

Explanation:

The function print_backward takes a string as a parameter.

Then it creates a new variable revString to hold a resultant string in opposite order.

The loop iterates through the characters of given string parameter in reverse and adds each character of the string to revString in opposite order.

Then the function returns revString which is the string in opposite order.

document.write(print_backward("hello there!")) This statement calls print_backward method passing a string hello there! to the method in order to print/display the characters of string in opposite order.

Lets say the string is hello

Then the loop works as follows:

The variable i is initialized to string.length - 1

string.length returns the length of the string

The length of string is 5 as there are 5 characters in string hello.

Hence string.length - 1 = 5 -1 = 4. So i=4

The loop checks if the value of i is greater than or equals to 0. This is true because i=4

Then the program enters the body of the loop which has a statement:

revString += string[i]; this works as:

revString = revString + string[i];

As i = 4 So

At first iteration

revString = revString + string[4];

This means the last character of string hello is added to revString. The last character of hello is 'o'

revString = 'o'

The statement in loop body continues to execute and stops when the value of i becomes less than 0.

The value of is decremented by 1 i.e. i-- So i = 3

At second iteration

revString = revString + string[3];

This means the second from last character of string hello is added to revString. The second last character of hello is 'l'

revString = 'ol'

The value of is decremented by 1 i.e. i-- So i = 2

At third iteration

revString = revString + string[2];

This means the third from last character of string hello is added to revString. The third last character of hello is 'l'

revString = 'oll'

The value of is decremented by 1 i.e. i-- So i = 1

At fourth iteration

revString = revString + string[1];

This means the fourth from last character of string hello is added to revString. The fourth last character of hello is 'e'

revString = 'olle'

The value of is decremented by 1 i.e. i-- So i = 0

At fifth iteration

revString = revString + string[0];

This means the fifth from last character of string hello is added to revString. The fifth last character of hello is 'e'

revString = 'olleh'

The value of is decremented by 1 i.e. i-- and the loop breaks because the i>=0 evaluates to false.

So the program moves to the next statement:

return revString;

revString = 'olleh' is returned and the statement document.write(print_backward("hello")) prints olleh on output screen.

In the given example the string is hello there! So this works same like the explained example and prints the following output on screen:

Output:

!ereht olleh

3 0
3 years ago
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