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spayn [35]
4 years ago
11

Write an algebraic expression that represents 2 less than 18 times a number: answer choices; 1. 18x-2, 2. 2-18x, 3. 2x-18

Mathematics
1 answer:
Jobisdone [24]4 years ago
4 0
A number would be x
18 times this number is 18x
2 less than 18 times a number is 18x-2
1. 18x-2
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Consider the probability that no less than 95 out of 152 registered voters will vote in the presidential election. Assume the pr
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Answer:

0.3821 = 38.21% probability that no less than 95 out of 152 registered voters will vote in the presidential election.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

Assume the probability that a given registered voter will vote in the presidential election is 61%.

This means that p = 0.61

152 registed voters:

This means that n = 152

Mean and Standard deviation:

\mu = E(X) = 152*0.61 = 92.72

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{152*0.61*0.39} = 6.01

Probability that no less than 95 out of 152 registered voters will vote in the presidential election.

This is, using continuity correction, P(X \geq 95 - 0.5) = P(X \geq 94.5), which is 1 subtracted by the pvalue of Z when X = 94.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{94.5 - 92.72}{6.01}

Z = 0.3

Z = 0.3 has a pvalue of 0.6179

1 - 0.6179 = 0.3821

0.3821 = 38.21% probability that no less than 95 out of 152 registered voters will vote in the presidential election.

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