Answer: The second option, y = 3(1/3)^x
Step-by-step explanation: Input each equation into a graphing calculator (preferably GeoGebra online) and check the answer. I linked the equation, but make sure to check anyway just in case :)
Answer:
See solutions below
Step-by-step explanation:
a) Given the expressions
x³y and x⁴y³
Find their factors
x³y = (x * x * x * y)
x⁴y³ = (x * x * x * y) * x * y * y
GCF = x*x*x*y
GCF = x³y
The expressions in parenthesis is the GCF. Hence the GCF of x³y and x⁴y³ is x³y
b) For 48m⁶n⁵p⁴ and 20m⁴n⁵p⁶
48m⁶n⁵p⁴ =12 * (4 * m⁴ * n⁵ * p⁴) * m²
20m⁴n⁵p⁶ = 5 * (4 * m⁴ * n⁵ * p⁴) * p²
GCF is the expression common to both terms
GCF = 4 * m⁴ * n⁵ * p⁴
GCF = 4m⁴n⁵p⁴
The amount in gallons of each milk containing 9% butterfat and milk containing 4% butterfat which must be used to obtain the desired 365 gallons are;
- 219 gallons of 9% fat.
- 146 gallons of 7% fat.
<h3>What quantity of each type of milk is required for the desired 365 gallon?</h3>
It follows from the task content that the quantity of each type of milk required to arrive at the targeted fat content and quantity of milk are to be determined.
Let x = quantity of 9% fat milk and
Let y = quantity of 4% fat milk
Therefore, by mass balance; we have;
x + y = 365.
Where; y = 365 - x.
Also, by fat balance; we have;
(9% × x) + (4% × y) = (7% × 365)
9x + 4y = 2555
Therefore, the two equations to be solved simultaneously by substituting y from the first equation into the second equation as follows;
9x + 4 (365 - x) = 2555
5x = 1095
x = 1095/5
x = 219 gallons.
Also, y = 365 - 219 = 146 gallons.
Read more on simultaneous equations;
brainly.com/question/16863577
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Answer:
Step-by-step explanation:
1.4 is 10 decimal places away from 0.00000000014