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Alex73 [517]
3 years ago
15

Which of these pairs are equal?

Mathematics
1 answer:
AVprozaik [17]3 years ago
4 0

Answer: sin 33° and cos 57°

Step-by-step explanation:

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An artist mixes yellow an blue paint to make the perfect shade of green. she uses 2 ounces of blue paint for every 7 ounces of y
Julli [10]

Answer:

14 ounces of blue paint

Step-by-step explanation:

The ratio of blue to yellow is 2:7

To solve this problem we can make a proportion:

2/7=x/49

the numerator represents the blue paint, the denominator represents the yellow paint

To solve the proportion you have to cross multiply:

2*49=7*x

x=14

She needs to add 14 oz of blue paint

I hope this helps :)

6 0
3 years ago
The expression means the product of 5 and the difference of three times r minus 10. If r = 4, the value of the expression is .
Morgarella [4.7K]

Answer:

10

Step-by-step explanation:

"three times r" = 3r

"three times r minus ten" = 3r - 10

"product of 5 and the difference of three times r minus ten"

= 5 (3r - 10)

given that r = 4,

the expression becomes

5 (3r - 10)

= 5 [3(4) - 10]

= 5 [12 - 10]

= 5 (2)

= 10

4 0
3 years ago
What is 3/5 + 1/10, 3/5+9/10, 1/4+5/6, 3/8+1/12, 2/5+2/7 in simplest form I will give brainliest for correct answer.
forsale [732]

Answer:

7/10, 3/2, 13/12, 11/24, and 24/35

8 0
3 years ago
Here are two rectangles.
Sophie [7]

Answer:

AB=9.5\ cm

Step-by-step explanation:

step 1

Find the length side PQ

we know that

The area of rectangle PQRS is given by

A=(PQ)(QR)

A=66\ cm^2

so

66=(PQ)(QR)

substitute the value of QR

66=(PQ)(12)

solve for PQ

PQ=66/12\\PQ=5.5\ cm

step 2

Find the length side AB

we know that

The perimeter of rectangle ABCD is given by

P=2(AB+BC)

we have

P=30\ cm\\BC=PQ=5.5\ cm

substitute

30=2(AB+5.5)

solve for AB

15=AB+5.5\\AB=15-5.5\\AB=9.5\ cm

6 0
3 years ago
Solve 3/4•1/7 in lowest terms
emmasim [6.3K]

Answer:

3/28

Step-by-step explanation:

\frac{3}{4}*\frac{1}{7}=\frac{3}{4*7}=\frac{3}{28}

that dot is a multiplication sign, right?

3 0
3 years ago
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