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matrenka [14]
3 years ago
5

Simplify (11 + 5i)(11 - 51)

Mathematics
2 answers:
Ede4ka [16]3 years ago
7 0

Answer:

 (146 +  0i)

Step-by-step explanation:

(11+5i)(11-5i)

The formula is :

(a+bi) • (x+yi)  = ax+by•i^2+(ay+bx)i

and since  i^2 = -1  it can be written as :

ax - by + (ay + bx) i

( 11 +  5i) • ( 11 -  5i) =

 (146 +  0i)

hope this helped brainlest owo???

mixas84 [53]3 years ago
3 0

Answer:

146

Step-by-step explanation:

(11 + 5i)(11 - 5i) =

Use the product of a sum and a difference, (a + b)(a - b) = a^2 - b^2.

= 11^2 - (5i)^2

= 121 - (25)(i^2)

= 121 - (25)(-1)

= 121 - (-25)

= 121 + 25

= 146

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Answer:

a = \frac{14 - b}{5}

Step-by-step explanation:

The rule to know and follow is:

You can add, subtract, multiply or divide by anything so long as the same thing is done to both sides of the equals sign;

5a + b = 14

If we want to get: "a = ...", then we use the rule to isolate the variable a on one side of the equation;

Firstly, we subtract b from both sides:

5a + b - b = 14 - b

5a = 14 - b

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\frac{5a}{5} = \frac{14 - b}{5} \\\\ a = \frac{14 - b}{5}

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  1. The revenue as a function of x is equal to -x²/20 + 920x.
  2. The profit as a function of x is equal to -x²/20 + 840x - 6000.
  3. The value of x which maximizes profit is 8,400 and the maximum profit is $3,522,000.
  4. The price to be charged to maximize profit is $500.

<h3>How to express the revenue as a function of x?</h3>

Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.

Mathematically, the revenue can be calculated by using the following expression:

R(x) = x × P(x)

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Revenue, R(x) = x(-x/20 + 920)

Revenue, R(x) = -x²/20 + 920x.

Expressing the profit as a function of x, we have:

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = -x²/20 + 920x - (80x + 6000)

P(x) = -x²/20 + 840x - 6000.

For the value of x which maximizes profit, we would differentiate the profit function with respect to x:

P(x) = -x²/20 + 840x - 6000

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P(x) = -x²/20 + 840x - 6000

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P(8400) = -3,528,000 + 7,056,000 - 6000

P(8400) = $3,522,000.

Lastly, we would calculate the price to be charged in order to maximize profit is given by:

P(x) = -1/20(x) + 920

P(x) = -1/20(8400) + 920

P(x) = -420 + 920

P(x) = $500.

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