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Mashcka [7]
2 years ago
11

1. A family is building a circular fountain in the backyard. The yard is rectangular and measures 10x by 15x and the fountain is

going to be circular with a radius of 4x. Once the fountain is built, what will be the area of the remaining yard?
2. A sports team is building a new stadium on a rectangular lot of land. The lot measures 8x by 12x and the field will be 3x by 6x. How much land will be left for the bleachers, restrooms, and other parts of the stadium?
Mathematics
1 answer:
sp2606 [1]2 years ago
7 0
1. The remaing area of the yard will be found as follows:
Area of the yard

A1=length*width=10x*15x=150x^2 yd^2

area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2

The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2


2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2 

Area of the field
A2=length×width
A2=3x×6x=18x^2

Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units


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For this case we must find an expression equivalent to:

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x ^ 3 * \frac {1} {y ^ 7} =\\\frac {x ^ 3} {y ^ 7}

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\frac {x ^ 3} {y ^ 7}

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Yolanda wants to pour 91.48 grams of salt into a container so far she has poured 72.2 grams how much more salt should Yolanda po
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19.28

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Answer:

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To simplify first factorize both the numerator and the denominator

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Rewrite -xy as a difference

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Factorize

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So we now have

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<h2>\frac{5(x + 2y)}{x - 3y}</h2>

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Step-by-step explanation:

Given expression is:

\frac{x^{2}-9 }{(x-1)(x-3)}

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\frac{(x+3)(x-3)}{(x-1)(x-3)}

Since x ≠ 3, let us cancel the common factor x - 3 in the numerator and in the denominator.

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