To solve this problem you must apply the proccedure shown below:
1. You have that 
and 
, therefore, you must divide must fucntion, as following:
2. You must simplify it,by factoring out 
, as following:
3. Finally, you obtain that the answer is:
Using proportions, supposing a scale of 1 inch = 3 feet, the actual measurements of her bed are given by: 9 ft x 18 ft.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and equations can be built to find the desired measures in the problem using basic arithmetic operations such as multiplication or division, from the relations built in the problem.
One example of application of proportions is for scale problems, as the actual scale and the drawing length are compared to find the actual length of the object drawn.
In the context of this problem, the scale is given by:
1 inch = 3 feet.
The drawn length of the bed is given by:
3 inches x 6 inches.
Hence the actual length is given by:
9 feet x 18 feet.
As:
<h3>What is the missing information?</h3>
The scale of the drawing is missing, hence we are going to suppose that it is 1 inch = 3 feet.
More can be learned about proportions at brainly.com/question/24372153
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Answer:
Step-by-step explanation:
im pretty sure its A, B, D
Hope this helps!
-Delilah
Answer:
259.99
Step-by-step explanation:
You look at the hundreths place and see if the number behind it is bigger than 5, and if it is then you up it by one, and if it's 4 and below then you round it to zero. In this case you up it by one and you get 269.99.
I hope this helps!!!!
Answer:
plot the points (0, 2) and (π, 4)
Step-by-step explanation:
To use your sine plotting tool, you need two points on the graph. The midline point is given for you. It is the y-intercept, (0, 2).
The maximum amplitude point is 1/4 of a period from this midline point. The frequency is 1/(4π), and the period is the inverse of frequency:
T = 1/f = 4π
So, 1/4 of a period is ...
T/4 = (4π)/4 = π
The peak value of the function is the amplitude added to the midline, so is 2+2 = 4.
The second point you need to plot is the peak value, (π, 4).
Your points are (0, 2) and (π, 4).
