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il63 [147K]
3 years ago
5

What is the amount of money , P, that will generate $40 in interest at a 10% interest rate over 5 years ?

Mathematics
2 answers:
EastWind [94]3 years ago
7 0

Answer:

The amount of money is 60$

Step-by-step explanation:

Given,         Principal, P = $40

                   Rate, R = 10%

                   Time, T = 5 years

We have to calculate the amount A = S.I + P

             S.I =\frac{ P\times R \times T}{100}

⇒           S.I = \frac{40\times 10\times 5}{100}

                          =  20

Hence, Amount = S.I + P

                            = 20 + 40 = 60$

zhenek [66]3 years ago
3 0
The formula is
I=prt
I interest earned 40
P principle ?
R interest rate 0.1
T time 5years
Solve for p to get
P=I÷rt
P=40÷(0.1×5)
P=80
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7^4

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3 years ago
1)The computer accessory that Joanne is considering
ankoles [38]

Answer:

Check Explanation.

Step-by-step explanation:

- A sample space includes all the possible outcomes of a statistical event. It refers to all the possible results, values that a statistical event can take on.

- Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

a) Joanne is considering selling a computer accessory at her store and the accessories come in white, beige, gray or black and as an optical mouse, mechanical mouse or trackball.

This means that an accessory can be white and an optical mouse, white and a mechanical mouse or white and a trackball.

This can be done for the 3 other colours.

So, the sample space for the accessory spans:

(white, optical mouse), (white, mechanical mouse), (white, trackball), (beige, optical mouse), (beige, mechanical mouse), (beige, trackball), (gray, optical mouse), (gray, mechanical mouse), (gray, trackball), (black, optical mouse), (black, mechanical mouse), (black, trackball)

The probability that someone gets beige and a mechanical mouse

Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

Number of outcomes with an accessory that is beige and a mechanical mouse = 1

Number of events in the sample space = 12

The probability that someone gets beige and a mechanical mouse = (1/12) = 0.0833

b) Jackie has three pairs of jeans: Joe Brand, Levis and Seven. She also has 4 tops: red, blue, purple and pink.

The sample space for Jackie's outfits is;

(Joe Brand, red), (Joe Brand, blue), (Joe Brand, purple), (Joe Brand, pink), (Levis, red), (Levis, blue), (Levis, purple), (Levis, pink), (Seven, red), (Seven, blue), (Seven, purple), (Seven, pink)

The chance she wears the Joe Brand or Levis and a purple top.

Number of outcomes with an outfit of Joe Brand or Levis and a purple top = 2

number of outfits on the sample space = 12

The chance she wears the Joe Brand or Levis and a purple top = (1/6) = 0.1667

c) A surfer owns 5 wetsuits: brown, black, pants, shorts and green. He also owns 3 surf boards: blue, green and red.

Sample space includes

(brown, blue), (brown, green), (brown, red), (black, blue), (black, green), (black, red), (pants, blue), (pants, green), (pants, red), (shorts, blue), (shorts, green), (shorts, red), (green, blue), (green, green), (green, red)

The chance he has a green wetsuit and surfboard

Number of outcomes in the sample space with green wetsuit and a green surfboard = 1

number of outcomes in the sample space = 15

The chance he has a green wetsuit and surfboard = (1/15) = 0.0667

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