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Sati [7]
4 years ago
13

Divide the binomial by the monomial to find the quotient -36x^4y + 144x^2 y^6/ -4x^2y

Mathematics
2 answers:
elixir [45]4 years ago
8 0
The way that you would do this is by taking -4x^{2} out of the binomial, or as I like to think about it, 'un-distributing'. :p
-4x^{2} out of -36x^{2}y, you end up with 12x^{2}. 
When you take -4x^{2} out of 144x^{2}y{6}, you get -36y^{5}. 
Put it together, and the solution is 12x^{2} - 36y^{5}.

Hope I helped!!
 
sp2606 [1]4 years ago
4 0
<h2>Answer:</h2>

The quotient is:

                       9x^2-36y^5

<h2>Step-by-step explanation:</h2>

We are asked to find the quotient when a binomial is divided by the monomial.

The expression is as follows:

\dfrac{-36x^4y+144x^2y^6}{-4x^2y}

on taking out the common factors from the numerator term of the expression we get:

-36x^4y+144x^2y^6=36x^2y(-x^2+4y^5)

Hence, we get:

\dfrac{-36x^4y+144x^2y^6}{-4x^2y}=\dfrac{36x^2y(-x^2+4y^5)}{-4x^2y}\\\\\\\dfrac{-36x^4y+144x^2y^6}{-4x^2y}=-9(-x^2+4y^5)\\\\\\i.e.\\\\\\\dfrac{-36x^4y+144x^2y^6}{-4x^2y}=9(x^2-4y^5)

          Hence, the quotient is:

             9x^2-36y^5

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