Question

Divide the binomial by the monomial to find the quotient -36x^4y + 144x^2 y^6/ -4x^2y

Answer 1

The way that you would do this is by taking $-4x^{2}$ out of the binomial, or as I like to think about it, 'un-distributing'. :p
$-4x^{2}$ out of $-36x^{2}y$, you end up with $12x^{2}$. 
When you take $-4x^{2}$ out of $144x^{2}y{6}$, you get $-36y^{5}$. 
Put it together, and the solution is $12x^{2}$ - $36y^{5}$.

Hope I helped!!
 

Answer 2

Answer:

The quotient is:

                       $9x^2-36y^5$

Step-by-step explanation:

We are asked to find the quotient when a binomial is divided by the monomial.

The expression is as follows:

$\dfrac{-36x^4y+144x^2y^6}{-4x^2y}$

on taking out the common factors from the numerator term of the expression we get:

$-36x^4y+144x^2y^6=36x^2y(-x^2+4y^5)$

Hence, we get:

$\dfrac{-36x^4y+144x^2y^6}{-4x^2y}=\dfrac{36x^2y(-x^2+4y^5)}{-4x^2y}\\\\\\\dfrac{-36x^4y+144x^2y^6}{-4x^2y}=-9(-x^2+4y^5)\\\\\\i.e.\\\\\\\dfrac{-36x^4y+144x^2y^6}{-4x^2y}=9(x^2-4y^5)$

          Hence, the quotient is:

             $9x^2-36y^5$