The answer to your question is 20
Answer:
03%
Step-by-step explanation:
In this situation Mickey should have drew first 7 cards that are not diamond and then on the 8th attempt she should draw an ace.
Let A be the event of drawing 7 cards which are not diamond and B the event of drawing an ace card. therefore required probability is P(A∩B)=P(A)*P(B)
Now, there are 13 diamonds and 39 other cards. Hence,
P(A)=(
)⁷=0.1335
After drawing 7 non-diamond cards, the 8th card must be a diamond.Hence,
P(B)=
=0.25
Hence, P(A∩B)=P(A)*P(B)=0.1335*0.25=0.033(approximately 0.03,i.e. 3%)
Therefore probability that Mickey will draw her first diamond on the 8th
attempt is 3%
Let the numbers be x&y
X+y=109
Taking a as the smallest number we multiply by 4
So according to the question you will have this equation
Y(as the largest number) -4x=4. Y-4x=4
Then find y
Y=4x+4
Substitute y on the first equation to get a
X+y=109
X+4x+4=109
X=21
21+y=109
Y=88
HOPE IT HELPS PLS MARK AS BRAINLIEST
B. One arm extended straight to the side
website: scoutlife.org
Children=x
Adults=y
* x + y =275 => x = 275 - y
* 3.00x + 6.40y = 1284 <=> 3.00(275 - y) + 6.40y = 1284 <=> ... <=> y = 135 => x = 275 - 135 = 140
Children: 140
Adults: 135