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elena-14-01-66 [18.8K]
3 years ago
9

What adaptations do robber crabs have ?

Biology
3 answers:
Karolina [17]3 years ago
8 0

The adaptations that a coconut crabs also known as a robber crab is they use a special organ called branchiostegal lung that they use to breathe which other crabs have. This organ is a developmental stage between gills and lungs and is one of the most significant adaptations of the a coconut crab.

lyudmila [28]3 years ago
7 0

The adaptations that a coconut crabs also known as a robber crab is they use a special organ called branchiostegal lung that they use to breathe which other crabs have. This organ is a developmental stage between gills and lungs and is one of the most significant adaptations of the a coconut crab.

Hitman42 [59]3 years ago
5 0

The adaptations that a coconut crabs also known as a robber crab is they use a special organ called branchiostegal lung that they use to breathe which other crabs have. This organ is a developmental stage between gills and lungs and is one of the most significant adaptations of the a coconut crab.

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En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
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Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

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