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qwelly [4]
3 years ago
12

In △MNO, m = 20, n = 14, and m∠M = 51°. How many distinct triangles can be formed given these measurements?

Mathematics
2 answers:
Schach [20]3 years ago
5 0
There is only one distinct triangle possible, with m∠N ≈ 33°.
Sindrei [870]3 years ago
4 0

Answer:

One obtuse scalene triangle

Step-by-step explanation:

Given that in a triangle MNO side m =20, side n =14 and angle m = 51

Angle N = sin inverse of (nsin M/m) =32.957 degrees

Angle O = 180-M-N =96.043 degrees

Side o = 25.592

There is one triangle only.

This is because angle N can have two values 32.957 or 147.043

But if m = 51 other angle cannot be 147.043 hence there is only one value for angle N.

When there is only one value for angle N, angle O also can have only one value

So no of triangles = 1

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