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navik [9.2K]
3 years ago
13

An isosceles triangle has slant height s and angle t opposite the base. Find a formula for the base length b in terms of the ang

le t and the slant height s.Find a formula for the enclosed area A in terms of t and s.
Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0

OK, let's try with no figure.  We have an isosceles triangle sides s,s, and b.

Opposite b is angle t.

Draw the altitude h to bisect t.  We have two right triangles, legs b/2 and h, hypotenuse s.  The angle opposite b/2 is t/2 so

sin(t/2) = (b/2)/s = b/2s

So we arrived at the first part,

b = 2s sin(t/2)

The area of a triangle with sides s,s and included angle t is

A = (1/2) s² sin t

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What’s number 11 (same directions as below)
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Answer:

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Step-by-step explanation:

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A plane made a trip to Miami and back. It flew 400mph on the way there and flew 450mph on the return trip. How long did the trip
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Answer:

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3 years ago
Write the equation of the line that passes through the points (-6, -9) and (7, 7).
Rus_ich [418]

Answer:

\displaystyle y + 9 = \frac{16}{13} ( x + 6 )

Step-by-step explanation:

The point-slope form of the equation of a line is:

y - k = m ( x - h )

Where m is the slope and (h,k) is a point through which the line passes.

Given a line passes through points A(x1,y1) and B(x2,y2), the slope can be calculated with the equation:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

We are given the points (-6,-9) and (7,7), thus the slope is:

\displaystyle m=\frac{7+9}{7+6}=\frac{16}{13}

Now we apply the point-slope formula using the point (-6,-9):

\mathbf{\displaystyle y + 9 = \frac{16}{13} ( x + 6 )}

This equation is expressed in the required format

6 0
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Helppp please i don’t know how to do this
zloy xaker [14]

Answer:

The slope is -2/3x, rise over run, and the y-axis it is 5. y=-2/3x+5

6 0
1 year ago
Read 2 more answers
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