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3 years ago

8

Which relationship describes angles 1 and 2

1 answer:

solong [7]3 years ago

7 0

A. Vertical angles.

Complementary angles are adjacent angles that add to equal 90 degrees.
Adjacent angles are angles that share a side (they are right next to each other).
Supplementary angles are adjacent angles that add to equal 180 degrees.

Thus the answer is A.

Hope this helps.

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80 members decreased by 65%

prisoha [69]

There are now 28 members
all you do is 80 times 0.65 = 52
but you still have to subtract 80 - 52 to find the number of members left
SOOOO
28 members still there
52 members quit

7 0

3 years ago

Read 2 more answers

Solve y-12/25=3 1/5. What number is y?<br><br> A. 3 1/5<br> B. 3 17/25<br> C. 3 7/25<br> D. 4 17/25

kicyunya [14]

Answer:

Option c) y= $3\frac{17}{25}$ is correct

The value of y is 3 $\frac{17}{25}$

Step-by-step explanation:

Given equation is

$y-\frac{12}{25}=3\frac{1}{5}$

To solve the given equation for y

$y-\frac{12}{25}=3\frac{1}{5}$

$y-\frac{12}{25}=\frac{16}{5}$ (converting mixed fraction to normal fraction )

$y-\frac{16}{5}=\frac{12}{25}$

$y-\frac{(16\times 5)+12}{25}$ (taking LCM 25 )

$=\frac{80+12}{25}$ (adding the terms )

$y=\frac{92}{25}$ (now convert fraction into mixed fraction )

Therefore y= $3\frac{17}{25}$

Option c) y= $3\frac{17}{25}$ is correct

The value of y is 3 $\frac{17}{25}$

6 0

3 years ago

I need help please and thank you

Fynjy0 [20]

Answer:

4

Step-by-step explanation:

y=mx+c,m(4) is the slope

4 0

3 years ago

A farmer sold 54 pumpkins the first weekend of a fall festival and 42 pumpkins the second weekend. Which expression uses the dis

malfutka [58]

?-54-42=?
I hoped this helped

4 0

3 years ago

Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

$k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0$

$k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0$

$3\cdot k^{3} - 3\cdot k - 1 = 0$

7 0

3 years ago