All categories

3 years ago

Find an equation of the line L. L is perpendicular to y=-2x and is passing through points 2,-4

Mathematics

1 answer:

galina1969 [7]3 years ago

6 0

slope of line y= -2x is -2

slope of line L= (-1)reciprocal of slope line y= -2x.

=( -1)(-1/2)

=1/2

since the L passes through (2,-4),

equation of line L: y-(-4)= 1/2(x-2)

2y+8 = x-2

x-2y-10=0

Hence equation of line L is x-2y-10=0

You might be interested in

4.289 rounded to the nearest tenth

Novay_Z [31]

Answer:

4.3

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Can someone give me the pattern rule for 2 6 4 12 10 30 28 and wit are the next three numbers

Usimov [2.4K]

Multiply the first digit by 3 then subtract the answer by 2. Rule: x 3 - 2

5 0

3 years ago

Read 2 more answers

Prove that is here<br><img src="https://tex.z-dn.net/?f=1%20-%20cos%20%7B2%7Da%20%5Cdiv%201%20-%20sin%20a%7B2%7D%20%20%3D%20tan%

garri49 [273]

$\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}$

$\boxed{\sf \dfrac{cosA}{sinA}=cotA}$

$\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}$

$\\ \sf\longmapsto 1-cot2A$

$\\ \sf\longmapsto 1-\dfrac{1}{tan2A}$

$\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}$

$\\ \sf\longmapsto tan2A$

8 0

3 years ago

Sweets are sold loose, or pre-packed in 120g bags. The 120g bags are ?1.49 each. The loose sweets are ?0.89 for 100g. By calcula

tester [92]

Answer:

The loose sweets at ?0.89 for 100 g.

Step-by-step explanation:

First, calculate the price per gram. You do this by dividing the price by the grams.

?1.49 / 120 g = 1.49 / 120 = 0.0124 (4 dp)

Because the answer was very long, I have rounded it to 4 decimal places (4 dp).

?0.89 / 100 g = 0.89 / 100 = 0.0089

Next, you must calculate both pre-packed and loose sweets to the same weight. I am calculating them both to 100 g.

0.0124 x 100 = 1.24

0.0089 x 100 = 0.89

Finally, the cheapest product for 100 g will be the better value. In this case, it is the loose sweets.

6 0

3 years ago

Plzzz hurry up and help me if A+B=45<br>prove that <br>(1+tanA)(1+tanB)=2

Solnce55 [7]

Answer:

see explanation

Step-by-step explanation:

If A +B = 45° then tan(A+B) = tan45° = 1

Expanding (1 + tanA)(1 + tanB)

= 1 + tanA + tanB + tanAtanB → (1)

Using the Addition formula for tan(A + B)

tan(A+B) = $\frac{tanA+tanB}{1-tanAtanB}$ = 1 ← from above

Hence

tanA + tanB = 1 - tanAtanB ( add tanAtanB to both sides )

tanA + tanB + tanAtanB = 1 ( add 1 to both sides )

1 + tanA + tanB + tanAtanB = 2

Then from (1)

(1 + tanA)(1 + tanB) = 2 ⇒ proven

7 0

3 years ago