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IrinaK [193]
3 years ago
6

Round 2.449 to the nearest hundredth

Mathematics
2 answers:
arlik [135]3 years ago
7 0
The answer is 244? or 2
gregori [183]3 years ago
5 0
The answer will be 2.45, when rounded to the nearest hundredth.
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Express 150 as a product of PRIME FACTORS.<br>Answer:​
Flauer [41]

Answer:

Step-by-step explanation:

150=2X3X5X5\\ \\ 150=2(3)5^2

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2 years ago
Divide the polynomial (x^2 + 3x + 5) by 2x + 1​
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−2x=x2−6 Rewrite the equation by completing the square.
V125BC [204]

Answer:

(x + 1)² = 7

Step-by-step explanation:

Given:

-2x = x² - 6

We'll start by rearranging it to solve for zero:

x² + 2x - 6 = 0

The first term is already a perfect square so that's fine.  Normally, if that term had a non-square coefficient, you would need to multiply all terms a value that would change that constant to a perfect square.

Because it's already square (1), we can simply move to the next step, separating the -6 into a value that can be doubled to give us the 2, the coefficient of the second term.  That value will of course be 1, giving us:

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Now can group our perfect square on the left and our constants on the right:

x² + 2x + 1 - 7= 0

x² + 2x + 1 = 7

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To check our answer, we can solve for x:

x + 1 = ± √7

x = -1 ± √7

x ≈ 1.65, -3.65

Let's try one of those in the original equation:

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6 0
3 years ago
Whats the square root of 39 to the nearest integer
soldi70 [24.7K]

Answer:

To the nearest integer, the square root of 39 would be 6.

Step-by-step explanation:

To find the answer, look at the perfect squares on either side of 39. Lower than it would be 36 and the next highest would be 49. Since it is closer to 36, we can estimate that the answer is 6.

7 0
2 years ago
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Find the sum of all 11 terms of an AP whose middlemost terms is 30?
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Let the difference between consecutive terms be D. If the middle term is 30, then the term before it is 30-D, and the term after it is 30+D. So the sum of these three terms would be (30-D) + 30 + (30+D) = 3*30.

Extending this sum to include all 11 terms centered around 30, we see that any addition of D is canceled by a balanced subtraction, leaving you with 11 copies of 30. So the value of the sum is 11*30 = 330.

6 0
2 years ago
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