Solve for x by cross multiplying then isolating the variable:
cross multiply
15x=90 Isolate the variable
x=6
Solve for y by cross multiplying then isolating the variable:
cross multiply
9y=90 Isolate the variable
y=10
<span>Let n, n+2, and n+4 represent the three consecutive even integers. Or 2 in your case</span>
An integer is any whole number (not fractions) that can be either negative or positive.
1 is the only integer because 0.5 and 3/2 are not whole numbers and are fractions, while 1 is a whole number.
490 x 2/5 = 980/5 = 196 girls at Garland
945 x 5/7 = 4725/7 = 675 girls at Bowood
Bowood has more girls:
675-196 = 479 more
9514 1404 393
Answer:
(B) 4
Step-by-step explanation:
Consider the units column. The only sum of 3 and a single digit that will end in 1 is the sum ...
3 + 8 = 11
This tells you A = 8, so the top number is 1983, and the middle number is B78.
Considering the first two columns, we know that 83 +78 = 161, so there must be a carry of 1 into the third column. That makes it have the sum ...
1 + 9 + B = <something ending in 4>
We know the something cannot be 04 or 24, so must be 14. Then ...
10 + B = 14 ⇒ B = 4
__
So, the whole sum is ...
1983 +478 = 2461
and the letter values are ...
