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maxonik [38]
3 years ago
15

Find the product of the complex number and it's conjugate. 9-5i

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
Conjugate of 9-5i is 9+5i
product of those two: (9-5i)*(9+5i) = 9^{2} - (5i)^{2} =81-25* i^{2} =81-25*(-1)=81+25=106
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Answer:

t _{critical} = 1.760

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The percentage of the variance is;

r^2 = \dfrac{t^2}{t^2 + df}

r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}

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