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3 years ago

Answer please...................

Mathematics

1 answer:

Debora [2.8K]3 years ago

5 0

It means that all values of x would make it true. Also take a look at the equation when we simplify:

4x + 7 = 1 + 4x + 6
Which simplified turns into
4x + 7 = 4x + 7

So no matter what value you put for x, it will be the same on both sides, making all values true for x.

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Find the value of x, rounded to the nearest tenth?

Stolb23 [73]

Answer:

Step-by-step explanation:

we can use the trigonometric function in a right triangle

cos x = adjacent side to the angle /hypothenuse

cos 36°= x/10 ; multiply both sides by 10

10 * cos 36° = x ; make sure your calculator mode is in degrees

8.1 = x

4 0

3 years ago

What is the area of this figure

Dimas [21]

Cut the figure into two parts
area of a rectangle is length x width
10x5=50m
2x4=8
add them together
50+8=58

4 0

2 years ago

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun

AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

Nonsmokers Light Smoker Heavy smoker Total

Men 303 35 37 375

Women 413 31 45 489

Total 716 66 82 864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

$82C2=\frac{82!}{2!(82-2)!}=3321$

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

$864C2=\frac{864!}{2!(864-2)!}=372816$

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

$P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908$

4 0

3 years ago

Which inequality explains why these three segments cannot be used to construct a triangle?

Anna11 [10]

Answer:

Iliana cannot construct a triangle because the sum of the two smaller sides will not be greater than the third side. Iliana cannot construct a triangle because the sum of the two smaller sides will be greater than the third side.

5 0

2 years ago

Which of the following statements is true if m∠E = m∠Y and m∠F = m∠X?

mars1129 [50]

Answer:

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If m∠E = m∠Y and m∠F = m∠X

then

Triangles EFG and YXZ are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

The corresponding sides are

FE and XY

EG and YZ

GF and ZX

so therefore

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

Let us now tackle the problem!

A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.

From the figure in the attachment , we can conclude that:

m∠E = m∠Y

m∠F= m∠X

m∠G = m∠Z

∴ ΔEFG ~ ΔYXZ ( ΔEFG is similar to ΔYXZ )

Because of the similarity , then:

FE : XY = EG : YZ = GF : ZX

Conclusion:

ΔFG is similar to ΔYXZ.

Segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX , i.e:

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

3 0

2 years ago

Read 2 more answers