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leonid [27]
1 year ago
6

What is Orthocentre?

Mathematics
1 answer:
Aloiza [94]1 year ago
3 0

The intersection of altitudes traced perpendicularly from a triangle's vertices to its opposite sides is known as an orthocenter.

Given that,

We have to find what is orthocenter.

We know that

<h3>What is Orthocenter?</h3>

The intersection of altitudes traced perpendicularly from a triangle's vertices to its opposite sides is known as an orthocenter. It is the location in a triangle where the three angles of the triangle intersect. An orthocenter's three primary characteristics are as follows:

Triangle: A three-sided polygon with three edges.

A triangle's height is the line that runs between its vertices and perpendicular to the other side. A triangle can therefore have three heights, one from each vertices.

Vertex - A vertex is the intersection of two or more lines.

To learn more about orthocenter visit: brainly.com/question/19763099

#SPJ4

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2 years ago
let f(x)= p+ 8/x-q. the line x=4 is a vertical asymptote to the graph of f. what is the value of q and p, if the y intercept is
svlad2 [7]

Answer:

The value of q and p is 4 and -24  respectively.

Step-by-step explanation:

Being f(x)=\frac{p+8}{x-q} , the line x=4 is a vertical asymptote to the graph of f(x).  The line r is an asymptote of a function if the graph of the function is infinitely close to the line r. That is, an asymptote is a line to which a function approaches indefinitely, without ever touching it.

Being a rational function that which can be expressed as the quotient of two polynomials, a vertical asymptote occurs when the denominator is 0, that is, where the function is not defined. In this case:

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Being the line x=4 the vertical asymptote, then

<u><em>4=q</em></u>

Then the function f (x) is:

f(x)=y=\frac{p+8}{x-4}

The y intercept is (0,4). This is, x= 0 and y=4. Replacing:

4=\frac{p+8}{0-4}

Solving:

4=\frac{p+8}{-4}

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<u><em>The value of q and p is 4 and -24  respectively.</em></u>

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