Question

On a coordinate plane, a solid straight line has a positive slope and goes through (negative 4, 1) and (0, 3). Everything below and to the right of the line is shaded. Which linear inequality is represented by the graph?

Answer 1

Answer:

x - 2y + 6 > 0

Step-by-step explanation:

The equation of the straight line passing through the points (-4,1) and (0,3) on the coordinate plane is given by  

$\frac{y - 3}{3 - 1} = \frac{x - 0}{0 - (- 4)}$

⇒ 2(y - 3) = x

⇒ x - 2y + 6 = 0

Now, everything below and to the right of the line is shaded.

Hence, the linear inequality that is represented by the graph is x - 2y + 6 > 0 (Answer)