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oksian1 [2.3K]
3 years ago
8

What is 56÷34×y and add 12

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
7 0
Hey there! :)

PARENTHESES
EXPONENTS
MULTIPLICATION
DIVISION
ADDITION
SUBTRACTION

First is dividing

56 ÷ 34 = 56/34

56/34 = 28/17

56 ÷ 2 = 28
34 ÷ 2 = 17

Then multiply by y

28/17 × y = 28/17·y = 28y/17 or 28/17y

At last, you add 12

28y/17 + 12 = 28y/17 + 12

Your answer is: 28y/17 + 12

Hope this helps :)



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To find the y-intercept you first need to set everything equal to y and that will put everything in the y=mx+b line equation. Where m is the slope and b is the y intercept


x+3y = 14           subtract x over

3y = -x+14         divide by 3

y = -1/3x +14

So 14 is the y-intercept of the equation


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One palm tree grew 85 inches in 5 years and a queen palm tree grew 96 inches in 8 inches which tree grew faster explain
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Answer:

The queen palm tree

Step-by-step explanation:

I think you were saying years not inches but pretty much if you divide 85 divided by 5 you get 17 but if you divided 86 divided by 8 you get 12 so 12 is less than 17.

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The sum of two numbers is 436. The larger number is 3 times the smaller number. What are the numbers?
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The numbers are 109 and 327. Hope it helps!
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Write the point-slope form of the equation for a line that passes through (6,-1) with a slope of 2​
Vika [28.1K]

Answer: y + 1 = 2(x-6)

Step-by-step explanation:

Point Slope Form is y-y₁=m(x-x₁), and all you have to so is substitute in the values that you were given. So, the slope is 2, so you substitute that value in for m. Then, you substitute 6 in for x₁ (because 6 is the x value of the coordinate you were given) and you substitute -1 for y₁ (and it becomes positive because two negatives make a positive)

Hope this was helpful! Please feel free to ask me any questions!

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Given the rectangle abcd shown below has a total area of 72. E is in the midpoint of bc and f is the midpoint of dc. What is the
scoray [572]

Refer to the attached image.

Given the rectangle ABCD of length 'l' and height 'h'.

Therefore, CD=AB = 'l' and BC = AD = 'h'

We have to determine the area of triangle AEF.

Area of triangle AEF = Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

Area of triangle ADF = \frac{1}{2}bh

= \frac{1}{2}(DF \times AD)

= \frac{1}{2}(\frac{l}{2} \times h)

=\frac{lh}{4}

Area of triangle ECF = \frac{1}{2}bh

= \frac{1}{2}(CF \times CE)

= \frac{1}{2}(\frac{l}{2} \times \frac{h}{2})

=\frac{lh}{8}

Area of triangle ABE = \frac{1}{2}bh

= \frac{1}{2}(AB \times BE)

= \frac{1}{2}(l \times \frac{h}{2})

=\frac{lh}{4}

Now, area of triangle AEF =

Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

= 72 - (\frac{lh}{4} + \frac{lh}{8} + \frac{lh}{4})

= 72 - (\frac{2lh+lh+2lh}{8})

=72 - (\frac{5lh}{8})

=72 - (\frac{5 \times 72}{8})

=\frac{72 \times 8 - (5 \times 72)}{8}

= 27 units

Therefore, the area of triangle AEF is 27 units.

8 0
3 years ago
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