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KIM [24]
3 years ago
14

A new cream was developed to reduce the irritation caused by poison ivy. To test the effectiveness, researchers put an ad online

asking for volunteers to participate in the study. One hundred subjects replied, and they were informed that one group would receive the new cream and the other group would receive a cream with no active ingredient. All 100 subjects were exposed to poison ivy. Fifty were then assigned to the group with the new cream, and 50 were assigned to the group with the cream with no active ingredient. After three days, the subjects’ level of irritation was measured.
Of the 50 subjects that were assigned to the cream with no active ingredient, 15 stated they had less irritation. What is this called?

placebo
control group
placebo effect
placebo control
Mathematics
2 answers:
Charra [1.4K]3 years ago
8 0

Answer:

placebo effect

Step-by-step explanation:

edge 2020/2021

TEA [102]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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A 12- pack of 8- ounce juice boxes costs $5.90. How much would an 18- pack of the same 8- ounce juice boxes cost?
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Answer:

$8.85

Step-by-step explanation:

This a question of direct variation, so we can make out a relationship between the two factors. 12 is 2/3 of 18, so the cost of 12 would also be 2/3 of the cost of 18. We can now make an equation to solve.

\frac{2}{3} x=5.9\\2x=17.7\\x=8.85

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Read 2 more answers
Of the population of all fruit flies we wish to give a 90% confidence interval for the fraction which possess a gene which gives
maks197457 [2]

Answer:

The margin of error for the 90% confidence interval is of 0.038.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

To this end we have obtained a random sample of 400 fruit flies. We find that 280 of the flies in the sample possess the gene.

This means that n = 400, \pi = \frac{280}{400} = 0.7

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

Give the margin of error for the 90% confidence interval.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.645\sqrt{\frac{0.7*0.3}{400}}

M = 0.038

The margin of error for the 90% confidence interval is of 0.038.

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3 years ago
Consider the sequence.
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A set of buttons sells for $2.75 and costs $0.55 to make. Twenty percent of the profit (the difference between the purchase pric
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