Answer:
20%
Step-by-step explanation:
We can start by looking at it as a ratio, so 4 divided by 20 and 4/20 = 0.2, so that would be 20% viewing 1=100%.
Another way is
20 here is 100%, and for 20 to equal 100, we have to multiply it by 5. To balance it out, multiply the top by 5 as well, and 4 * 5 =20. Therefore, 4/20 = 20%
Answer:
636
Step-by-step explanation:
5xyz+3y
5(2.5)(12)(4)+3(12)
(12.5)(48)+36
600+36
636
Answer:
The common factors of 45 and 72 are 9, 3, 1
Step-by-step explanation:
Answer:
279 × 7 ≈ 2800
Step-by-step explanation:
if you have to round to the tens place, then both would be rounded up, the 7 to 10 and the 279 to 280. 10 × 280 = 2800
Complete question:
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.
A) Find the mean and standard deviation for the number of girls in groups of 36 births.
B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.
C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?
Answer:
a) mean = 18
Standard deviation =3
b) low range = 12
High range = 24
c) The result of 33 girls is significantly high. Yes, the method is effective.
Step-by-step explanation:
Given:
p = 0.5
n = 36
a) The mean is the product of n and p
Mean u = np
u = 36 * 0.5 = 18
The standard deviation is the square root of the product of n and p&q.
S.d ó = 


b) To find the range rule of thumb:
• For low range
Low range = u - 2ó
= 18 - (2 * 3)
= 12
• High range
= u + 2ó
= 18 + (2*3)
= 24
c) The result is significantly high, because 33 is greater than 24 girls.
A result of 33 girls would prove the method as effective.