PLEASE HELP ME IT'S DUE IN A COUPLE OF MINS

vovangra [49]

Answer:

s = 16.97 units

Step-by-step explanation:

Since this is a right triangle, we can use trigonometry to figure out the lengths of the sides.

Look at the 45 degree angle. We can use the opposite side (12) and the hypotenuse (s) to solve for s.

Opposite and hypotenuse is sine, so we are using sine. The sine of 45 degrees is 0.70710678118. Make an equation like so:

0.70710678118 = $\frac{12}{s}$ , and we are solving for s.

Put a 1 in the denominator of sine(45 degrees) so you can cross-multiply.

$\frac{0.70710678118}{1} =\frac{12}{s}$

Cross multiply.

0.70710678118s = 12

Divide both sides by sine(45 degrees).

s = 16.97

The length of side s is 16.97 units.

Another way to have done this problem is to use the Pythagorean theorem: a^2 + b^2 = c^2

Substitute 12 for a and b and solve for c, the hypotenuse.

(12)^2 + (12)^2 = c^2

Evaluate the exponents.

144 + 144 = c^2

Add them together.

288 = c^2

Square root 288 to solve for c.

c = 16.97, which is the same answer as you got using trigonometry.

6 0

3 years ago

Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th

Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 21-1 = 20$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have $T = 2.528$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{0.40}{\sqrt{21}} = 0.0873$

Now, we multiply T and s

$M = 2.528*0.0873 = 0.2207$

Then

The lower end of the interval is the mean subtracted by M. So:

$L = 3.27 - 0.2207 = 3.0493$

The upper end of the interval is the mean added to M. So:

$LCL = 3.27 + 0.2207 = 3.4907$

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0

3 years ago

What is the following quotient? StartFraction RootIndex 3 StartRoot 60 EndRoot Over RootIndex 3 StartRoot 20 EndRoot EndFraction

FrozenT [24]

Answer:

$\sqrt[3]{3}$

Step-by-step explanation:

We are required to simplify the quotient: $\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}$

Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:

$\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}$

$=\sqrt[3]{3}$

The simplified form of the given quotient is $\sqrt[3]{3}$ .

6 0

3 years ago

Read 2 more answers

Select the appropriate technique with the problem you are looking for.

Alenkinab [10]

Answer:

A, B, C, D

Step-by-step explanation:

(A) Checking the Equal Variance Assumption, the appropriate technique to use is:

- The ANOVA (Analysis of Variance) F test

- Plot residuals against fitted values

(B) Checking the Normal Assumption, the appropriate techniques to use are:

- Test for Kurtosis & Skewness

- Kolmogorov-Smirnov Test

- Q-Q Plots (the graphical method) also known as Quantile Plot

- Do not use a histogram; it is not advisable

(C) Checking for Model Misspecification, the appropriate techniques to use are:

- The Ramsey Regression Specification Error Test; also called RESET

- The Davidson & MacKinnon J. Test

(D) Checking for dependent errors, the appropriate technique to use is:

- Plot residuals against time variables

6 0

3 years ago

A woman starts out walking due north for 2 miles, and then she turns due west and continues for another 2 miles. How far from he

Mrac [35]

For this case we can model the problem as a rectangle triangle.
We have:
Length of the sides of the triangle.
We want to find:
Length of the hypotenuse.
Using the Pythagorean theorem we have:
$d ^ 2 = 2 ^ 2 + 2 ^ 2
$
$d = \sqrt{2 ^ 2 + 2 ^ 2} 

d = \sqrt{4 + 4} 

d = \sqrt{8} 

d = 2\sqrt{2} 
$
Answer:
She is:
$d = 2\sqrt{2}$
miles far from her starting point

4 0

3 years ago