An employee currently makes $10 per hour and will be given yearly raises if performance evaluations are satisfactory. Assuming a

Question

3 years ago

9

An employee currently makes $10 per hour and will be given yearly raises if performance evaluations are satisfactory. Assuming a

nnual evaluations are satisfactory, which statement is not correct? A) If the yearly raise is $3 per hour then the relationship is linear and the hourly rate "n" years from now will be h(n) = 10 + 3n for n = {1,2,3, ...}. B) If the yearly raise is 3% per hour then the relationship is exponential and the hourly rate "n" years from now will be h(n) = 10(1.03)n for n = {1,2,3, ...}. C) If the yearly raise is $3 per hour then the relationship is linear and the hourly rate "n" years from now will be h0 = 10 and hn = (hn − 1)(3) for n = {1,2,3, ...}. D) If the yearly raise is 3% per hour then the relationship is exponential and the hourly rate "n" years from now will be h0 = 10 and hn = (hn − 1)(1.03) for n = {1,2,3, ...}.

Mathematics

2 answers:

OleMash [197] · Answer 1 · 2022-01-25T18:23:43+03:00

OleMash [197]3 years ago

6 0

Answer:

C) If the yearly raise is $3 per hour then the relationship is linear and the hourly rate "n" years from now will be h0 = 10 and hn = (hn − 1)(3) for n = {1,2,3, ...}.

Step-by-step explanation:

j put c

puteri [66] · Answer 2 · 2022-01-25T20:34:50+03:00

Answer:

B) If the yearly raise is 3% per hour then the relationship is exponential and the hourly rate "n" years from now will be h(n) = 10(1.03)n for n = {1,2,3, ...}.

C) If the yearly raise is $3 per hour then the relationship is linear and the hourly rate "n" years from now will be h0 = 10 and hn = (hn − 1)(3) for n = {1,2,3, ...}.

D) If the yearly raise is 3% per hour then the relationship is exponential and the hourly rate "n" years from now will be h0 = 10 and hn = (hn − 1)(1.03) for n = {1,2,3, ...}.

Step-by-step explanation:

B is wrong because the yearly raise is $3 per hour, not 3% of the employees income.

C is wrong because the it eliminates the raise for year 1 (or the worker's second year). the worker's pay = $10 + [(1 - 1) x $3] = $10 + $0

D is wrong for the same reason as B.

Only option A was correct, the yearly salary is a linear function = 10 + 3n; at the end of the first year he will get a raise = $10 + $3 = $13, then next year the worker's salary = $16, then $19, etc.