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alina1380 [7]
3 years ago
8

Find the area of the trapezoid.

Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

141.12

Step-by-step explanation:

(12.2+10.2)/2*12.6=141.12

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Margin of error: 0.04; confidence level: 95%; from a prior study, bold p with bold overparenthesis on top is estimated by the de
GrogVix [38]

Answer: 235

Step-by-step explanation:

The formula to calculate the sample size  :-

n=(\hat{p}(1-\hat{p}))(\dfrac{z_{\alpha/2}}{E})^2

Given :  Estimated proportion \hat{p}=0.89

Margin of error : E=0.04

Significance level : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2} =1.96

Now, the required sample size will be :-

n=(0.89(0.11))(\dfrac{(1.96)}{0.04})^2

\Rightarrow\ n= 235.057\approx235

Hence, the required minimum sample size = 235

6 0
3 years ago
What is 30% of $40 and I don’t know what else to type
miskamm [114]

Answer:

30% of $40 would be $12

Step-by-step explanation:

To figure this out you can do cross multiplication. Take 30 over 100 like a fraction (30/100) and then that equals x over 40 (x/40), x being 30% of $40. then you would multiply diagonally. 100 times X and 30 times 40 getting you to 100x = 1200 then isolate the variable so there is no numbers with it, meaning you have to divide both sides by 100. 100x divided by 100= X and 1200 divided by 100= 12. So X=12, meaning 30% of $40 is $12.

6 0
3 years ago
Read 2 more answers
The scale model of a car is 5% of the size of the actual car. The length of
podryga [215]
<h3>Answer:  15 feet</h3>

Explanation:

x = length of the actual car in inches

5% of x = 9 inches

0.05x = 9

x = 9/(0.05)

x = 180 inches

Divide by 12 to convert from inches to feet.

180 inches = (180/12) feet = 15 feet

5 0
3 years ago
Write this product in its simplest form -5a•6a^8
timofeeve [1]
The rule for the product of similar bases with exponents:

(a^b)(a^c)=a^(b+c)

(-5*6)(a^1)(a^8)

(-30)(a^(1+8))

-30a^9
6 0
4 years ago
A runner covers 55 yards in 5.5 seconds. Find the runner's average speed in miles per hour.
marusya05 [52]
V=\frac{s}{t},where\ V-speed,\ s-distence\ ,t-time\\\\V=\frac{55y}{5,5s}=10\frac{y}{s}=10\frac{0,000568m}{\frac{1}{3600}h}=\frac{0,00568m}{\frac{1}{3600}h}=0,00568\cdot3600\frac{m}{h}=\\\\=20,448\frac{m}{h}
7 0
4 years ago
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