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Airida [17]
3 years ago
8

Which of the -values are solutions to the following inequality?

Mathematics
1 answer:
Andrej [43]3 years ago
3 0

We have been given an inequality 38. We are asked to choose the solutions of our inequality from given choices.

The solution of inequality are all values of x greater than 38.

Let us see our given choices one by one.

A. x=25

Since solution of inequality is greater than 38 and 25 is less than 38 , therefore, 25 is not a correct choice.

B. x=40

Since the solution of inequality is greater than 38 and 40 is greater than 38, therefore, 40 is the correct choice.

C. x=120

Since the solution of inequality is greater than 38 and 120 is greater than 38, therefore, 120 is the correct choice.

Hence x=40 and x=120 are solution for the given inequality.

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PLEASE HELP ASAP!!
BabaBlast [244]

Answer:

The first term of the sequence is -120.

Step-by-step explanation:

The formula for the "nth" term of a geometric sequence is shown below:

an = a0*r^(n-1)

Where an is the nth term, r is the ratio and n is the position of the term on the sequence. For this problem we want to find what is the initial term, a0, so we will isolate it in the formula as shown below:

a0*r^(n-1) = an

a0 = an/[r^(n-1)]

We then apply the data given to us

a0 = 31.45728/[-0.8^(7-1)]

a0 = 31.45728/[-0.8^6] =31.45728 /-0.262144= -120

The first term of the sequence is -120.

4 0
4 years ago
The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.10
Salsk061 [2.6K]

For the bell-shaped graph of the normal distribution of weights of Hershey kisses, the area under the curve is 1, the value of the median and mode both is 4.5338 G and the value of variance is 0.0108.

In the given question,

The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.1039 G.

We have to find the answer of many question we solve the question one by one.

From the question;

Mean(μ) = 4.5338 G

Standard Deviation(σ) = 0.1039 G

(a) We have to find for the bell-shaped graph of the normal distribution of weights of Hershey kisses what is the area under the curve.

As we know that when the mean is 0 and a standard deviation is 1 then it is known as normal distribution.

So area under the bell shaped curve will be

\int\limits^{\infty}_{-\infty} {f(x)} \, dx= 1

This shows that that the total area of under the curve.

(b) We have to find the median.

In the normal distribution mean, median both are same. So the value of median equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of median is also 4.5338 G.

(c) We have to find the mode.

In the normal distribution mean, mode both are same. So the value of mode equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of mode is also 4.5338 G.

(d) we have to find the value of variance.

The value of variance is equal to the square of standard deviation.

So Variance = (0.1039)^2

Variance = 0.0108

Hence, the value of variance is 0.0108.

To learn more about normally distribution link is here

brainly.com/question/15103234

#SPJ1

3 0
1 year ago
A(a-bx)/x=2/3<br> PLEASE
RSB [31]

Answer:

This cannot be solved but it can be simplified

first we open the bracket

so we have

a²- abx/x = 2/3

next we cross multiply so it will be 3(a² - abx) = 2x

we get

3a² - 3abx = 2x

Next we factorise so we can get

3a(a-bx) =2x

I dont know what exactly you where asked but I hop this helps

7 0
3 years ago
Holly has 65 stamps in het collection. To expand the collection, she is planning to buy some books of stamps
ahrayia [7]

Answer:

i think if she buys 5 books the she will have 90 stamps cuz 1 book cost 18 stamps then 5 books = <u>18x5=90</u>

Step-by-step explanation:

5 0
3 years ago
What is the aswer to 35.89÷3.7
Y_Kistochka [10]
If you just divide both you get 9.7
8 0
3 years ago
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