<span>12.6 • (–4) ÷ 12 • (–3) ÷ 0.5
= -50.4 </span>÷ 12 • (–3) ÷ 0.5
= -4.2• (–3) ÷ 0.5
= 12.6 ÷ 0.5
= 25.2
Answer:
The number of times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders is approximately 1.4
Step-by-step explanation:
From the question, the mean absolute deviation (MAD) of the sixth graders = 1.2 and that of the seventh graders = 1.7
The variability in the heights of the sixth graders = 1.2
The variability in the heights of the seventh graders = 1.7
To calculate how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders, we will divide the variability of the seventh graders by the variability of the sixth graders
That is, 1.7/ 1.2 = 1.4167 ≅ 1.4
Hence, the number of times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders is approximately 1.4
Answer:
B
Step-by-step explanation:
Using slope-intercept form, the slope is 3/2.
