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Zolol [24]
3 years ago
7

What is (f – g)(X); f (x) = x3 – 2x2 + 12x – 6 g(x) = 4x2 - 6x +4

Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0

Step-by-step explanation:

f-g(x)=x³-2x²+12x-6-(4x²-6x+4)

=x³-6x²+18x-10

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REAL LIFE A cylindrical hazardous waste container has a diameter of 1.5 feet and a height of 1.6 feet. Abo
aivan3 [116]

Answer:

It can hold up to 1.256ft^3 of waste

<em></em>

Step-by-step explanation:

Given

D = 1.5ft -- Diameter

h = 1.6ft -- height

Required

Determine the amount of waste it can hold

This simply means that we calculate the volume of the cylindrical container.

And this is calculated using:

Volume = \pi r^2h

Where

\pi = 3.14

and

r = \frac{D}{2}

r = \frac{1.5}{2}

r = 0.75

So, we have:

Volume = 3.14 * 0.5^2 * 1.6

Volume = 1.256ft^3

<em>Hence, it can hold up to </em>1.256ft^3<em> of waste</em>

3 0
3 years ago
Assume Cylinder A and Cone B are the same height and the bases have the same radius. If A has a volume of 18π cm3, what is the v
disa [49]

Answer:

Option A  V_B=19\ cm^3

Step-by-step explanation:

The volume of a cone is:

V_B = \pi\frac{hr ^ 2}{3}

The volume of a cylinder is:

V_A = \pi(r ^ 2)h

Both figures have the same height h and the same radius r.

The volume of the cylinderV_A = 18\pi\ cm ^ 3

We want to find the volume of the cone.

Then, we find r and h:

V_A = 18\pi = \pi(r ^ 2)h

We simplify.

V_A = 18 = (r ^ 2)h

Then the product of (r ^ 2)h = 18.

We substitute this in the cone formula and get:

V_B =\frac{\pi}{3}(18)\\\\V_B = \frac{18}{3}\pi\\\\V_B=19\ cm^3

8 0
3 years ago
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There are two glass 1 of them with salt solution and one with sugar solution
Brilliant_brown [7]

Answer:

how long question i did not found any answer

8 0
2 years ago
Will give brainliest for help
Naddika [18.5K]
What are you trying to find?
3 0
3 years ago
Read 2 more answers
9.a )Explain why plane JKL is not an appropriate
VLD [36.1K]

Answer:

I will attach the missing drawing with the answer.

9.b)

Plane JKM

Plane JLM

Plane KLM

Step-by-step explanation:

The drawing for this question is missing. I will attach it with the answer.

9.a) Plane JKL is not an appropriate name for the plane because all of three points lie in the same line.

Through a line pass infinite planes. The plane JKL doesn't define a unique plane. That's why plane JKL isn't an appropriate name for the plane.

9.b) We can name the plane using three points that don't lie in the same line.

Three possible names for the plane are :

Plane JKM

Plane JLM

Plane KLM

6 0
3 years ago
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