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2 years ago

Simply. Helppppppppp pleaseee

Mathematics

1 answer:

sp2606 [1]2 years ago

3 0

Answer:

(2p(p - y - 1) + y^2)) / (y - p)^y.

Step-by-step explanation:

p^2 / (y - p)^y - 2p / (y - p)^y + 1 / (y - p)^y-2

The LCD is (y - p)^y

NOTE : (y - p)^y / (y - p)^y-2 = (y - p)^(y - (y - 2)) = (y - p)^2

So we have

(p^2 - 2p + 1( (y - p)^2) / (y - p)^y

= ( p^2 - 2p +y^2 - 2py + p^2) / (y - p)^2

= (2p^2 - 2py - 2p + y^2) / (y - p)^y

= (2p(p - y - 1) + y^2)) / (y - p)^y.

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2 years ago

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