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Sliva [168]
2 years ago
6

Simply. Helppppppppp pleaseee

Mathematics
1 answer:
sp2606 [1]2 years ago
3 0

Answer:

(2p(p - y - 1) + y^2)) / (y - p)^y.

Step-by-step explanation:

p^2 / (y - p)^y - 2p / (y - p)^y + 1 / (y - p)^y-2

The LCD is (y - p)^y

NOTE : (y - p)^y /  (y - p)^y-2 = (y - p)^(y - (y - 2)) = (y - p)^2

So we have

(p^2 - 2p + 1( (y - p)^2) / (y - p)^y

= ( p^2 - 2p +y^2 - 2py + p^2) / (y - p)^2

= (2p^2 - 2py - 2p + y^2) / (y - p)^y

= (2p(p - y - 1) + y^2)) / (y - p)^y.

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Shobo's mother's present age is six times Shobo's present age. Shobo's age five
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Answer:

Step-by-step explanation:

Shobo's age = x years

His mother's age = 6 times of

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= 6x years

Five years from now

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Shobo's age = ( x + 5 ) years

According to the problem given,

x + 5 = one by third of his mother's

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x + 5 = 6x / 3

x + 5 = 2x

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Therefore ,

Shobo's present age = x = 5 years

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= 6 × 5

= 30 years

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Step-by-step explanation:

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